The probability of winning of a person is 6/11 and at a result he gets...
To calculate the expectation, we need to multiply the probability of winning by the amount won and subtract the probability of losing multiplied by the amount lost.
Given:
Probability of winning = 6/11
Amount won = Rs. 77/-
Amount lost = Rs. 0/- (since we only consider the amount won)
Let's calculate the expectation:
Step 1: Calculate the probability of losing
The probability of losing is 1 minus the probability of winning.
Probability of losing = 1 - 6/11 = 5/11
Step 2: Calculate the expectation
Expectation = (Probability of winning * Amount won) - (Probability of losing * Amount lost)
Expectation = (6/11 * Rs. 77/-) - (5/11 * Rs. 0/-)
Expectation = Rs. 42/-
Therefore, the expectation of this person is Rs. 42/-.
Explanation:
The concept of expectation is used to determine the average outcome of an event based on the probabilities and outcomes associated with it. In this case, the person has a probability of winning of 6/11, which means that out of 11 trials, the person is expected to win 6 times. The amount won in each trial is Rs. 77/-. On the other hand, the probability of losing is 5/11, which means that out of 11 trials, the person is expected to lose 5 times. Since there is no amount lost in this scenario, we consider the amount won as the only outcome.
To calculate the expectation, we multiply the probability of winning by the amount won and subtract the probability of losing multiplied by the amount lost. In this case, the expectation is calculated as (6/11 * Rs. 77/-) - (5/11 * Rs. 0/-), which simplifies to Rs. 42/-.
Therefore, the expectation of this person is Rs. 42/-. This means that on average, the person can expect to win Rs. 42/- per trial.