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Sum of three numbers is 54, and the first number is 10 more than the third and 10 less than the second number. Find the second number.
  • a)
    28
  • b)
    18
  • c)
    16
  • d)
    8
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Sum of three numbers is 54, and the first number is 10 more than the ...
Let first, second and third numbers are a, b and c respectively.
a + b + c = 54
b = a + 10
c = a - 10
a + a - 10 + a + 10 = 54
a = 18
second number = b = a + 10 = 18 + 10 = 28
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Most Upvoted Answer
Sum of three numbers is 54, and the first number is 10 more than the ...
Solution:

Let's assume the third number to be x.

According to the problem,

The first number = (x + 10)

The second number = (x + 10) + 10 = (x + 20)

Now, we know that the sum of these three numbers is 54.

So, x + (x + 10) + (x + 20) = 54

Simplifying the equation, we get:

3x + 30 = 54

3x = 24

x = 8

Hence, the third number is 8.

Now, we can find the second number using the equation we derived earlier:

Second number = (x + 20) = (8 + 20) = 28

Therefore, the second number is 28, which is option A.
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Sum of three numbers is 54, and the first number is 10 more than the third and 10 less than the second number. Find the second number.a)28b)18c)16d)8Correct answer is option 'A'. Can you explain this answer?
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