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A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m is
  • a)
    4 • 5 x 104 C ∕ K g
  • b)
    9 x 107 C ∕ K g
  • c)
    4 • 5 x 103 C ∕ K g
  • d)
    9 x 105 C ∕ K g
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A charged particle accelerated through a potential difference of 100V ...
We can use the equations for the motion of a charged particle in electric and magnetic fields to solve for the specific charge e/m.

In the electric field, the force on the particle is F = qE, where q is the charge of the particle and E is the electric field strength. The acceleration of the particle is then a = F/m = qE/m.

In the magnetic field, the force on the particle is F = qvB, where v is the velocity of the particle and B is the magnetic field strength. The acceleration of the particle is then a = F/m = qvB/m.

Since the particle is experiencing no deflection, the electric and magnetic forces must be equal and opposite, so we can set the two expressions for acceleration equal:

qE/m = qvB/m

Simplifying and rearranging:

e/m = v/B

We can solve for the velocity of the particle using the equation for the kinetic energy gained in the potential difference:

qV = 1/2 mv^2

Solving for v:

v = sqrt(2qV/m)

Substituting in the given values:

v = sqrt(2*1.6x10^-19*100/9.1x10^-31) = 6.05x10^6 m/s

Substituting in the given values for E and B:

e/m = v/B = (6.05x10^6)/(5x10^3) = 1.21x10^3 C/kg

Therefore, the specific charge e/m is 1.21x10^3 C/kg.
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A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V m and B = 5 x 103 T . The specific charge e/m isa)4 • 5 x 104 C K gb)9 x 107 C K gc)4 • 5 x 103 C K gd)9 x 105 C K gCorrect answer is option 'A'. Can you explain this answer?
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A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V m and B = 5 x 103 T . The specific charge e/m isa)4 • 5 x 104 C K gb)9 x 107 C K gc)4 • 5 x 103 C K gd)9 x 105 C K gCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V m and B = 5 x 103 T . The specific charge e/m isa)4 • 5 x 104 C K gb)9 x 107 C K gc)4 • 5 x 103 C K gd)9 x 105 C K gCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V m and B = 5 x 103 T . The specific charge e/m isa)4 • 5 x 104 C K gb)9 x 107 C K gc)4 • 5 x 103 C K gd)9 x 105 C K gCorrect answer is option 'A'. Can you explain this answer?.
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