JEE Exam > JEE Questions > A charged particle accelerated through a pote...
Start Learning for Free
A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m is
- a)4.5 x 104C ∕ K g
- b)9 x 107 C ∕ K g
- c)4.5 x 103 C ∕ K g
- d)9 x 105 C ∕ K g
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A charged particle accelerated through a potential difference of 100V ...
Solution:
Given, potential difference (V) = 100V, electric field (E) = 15 x 106 V/m, magnetic field (B) = 5 x 103 T.
The specific charge of the particle e/m is to be determined.
Particle in Electric Field:
When a particle of charge q and mass m is accelerated through a potential difference V, then the kinetic energy of the particle is given by
K.E = qV
The velocity acquired by the particle is given by
K.E = 1/2 mv2
v = sqrt(2K.E/m)
where qV = 1/2 mv2
Therefore, v = sqrt(2qV/m)
Particle in Magnetic Field:
When a charged particle enters a magnetic field, it experiences a force given by
F = qvBsinθ
where q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength and θ is the angle between the velocity vector of the particle and the magnetic field vector.
Particle in Combined Electric and Magnetic Field:
When a charged particle enters a region of combined electric and magnetic fields, it experiences a force given by
F = q(E + vBsinθ)
If the particle is not deflected, then the force experienced by the particle in the electric and magnetic fields is balanced by the force of the gravitational field. Therefore,
q(E + vBsinθ) = mg
Substituting the values of E, B, v and solving for e/m, we get
e/m = 4.5 x 104 C/kg
Therefore, the specific charge of the particle e/m is 4.5 x 104 C/kg, which is option A.
Given, potential difference (V) = 100V, electric field (E) = 15 x 106 V/m, magnetic field (B) = 5 x 103 T.
The specific charge of the particle e/m is to be determined.
Particle in Electric Field:
When a particle of charge q and mass m is accelerated through a potential difference V, then the kinetic energy of the particle is given by
K.E = qV
The velocity acquired by the particle is given by
K.E = 1/2 mv2
v = sqrt(2K.E/m)
where qV = 1/2 mv2
Therefore, v = sqrt(2qV/m)
Particle in Magnetic Field:
When a charged particle enters a magnetic field, it experiences a force given by
F = qvBsinθ
where q is the charge of the particle, v is the velocity of the particle, B is the magnetic field strength and θ is the angle between the velocity vector of the particle and the magnetic field vector.
Particle in Combined Electric and Magnetic Field:
When a charged particle enters a region of combined electric and magnetic fields, it experiences a force given by
F = q(E + vBsinθ)
If the particle is not deflected, then the force experienced by the particle in the electric and magnetic fields is balanced by the force of the gravitational field. Therefore,
q(E + vBsinθ) = mg
Substituting the values of E, B, v and solving for e/m, we get
e/m = 4.5 x 104 C/kg
Therefore, the specific charge of the particle e/m is 4.5 x 104 C/kg, which is option A.
Free Test
FREE
| Start Free Test |
Community Answer
A charged particle accelerated through a potential difference of 100V ...
As velocity =electric field/magnetic field =3(10*3) vq=1/2mv*2 q/m=4.5(10*4) by substituting values
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer?
Question Description
A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer?.
A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A charged particle accelerated through a potential difference of 100V passes through the uniform electric and magnetic fields so as to experience no deflection. E = 15 x 106 V ∕ m and B = 5 x 103 T . The specific charge e/m isa)4.5 x 104C ∕ K gb)9 x 107 C ∕ K gc)4.5 x 103 C ∕ K gd)9 x 105 C ∕ K gCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup