All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  For the dissociation reaction,H2 (g) → 2... Start Learning for Free
SaveJoin the Discussion on the App
For the dissociation reaction,
H2 (g) → 2H (g) ΔH = 162 Kcal,
heat of atomisation of H is
  • a)
    81 Kcal
  • b)
    162 Kcal
  • c)
    208 Kcal
  • d)
    218 Kcal
Correct answer is option 'A'. Can you explain this answer?
FREE This question is part of
Download PDF Attempt Test
Download PDF Attempt this Test
Verified Answer
For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal...
ΔH = ΔH(product) – DH(reactant)
162 = 2 × ΔHH -DHH2

ΔHH = 81 Kcal
View all questions of this test
Most Upvoted Answer
For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal...
The dissociation reaction of H2(g) can be represented as:

H2(g) ⟶ 2H(g)

This reaction represents the breaking of the H-H bond in hydrogen gas (H2) to form two hydrogen atoms (H).
< Previous Question Next Question >
Explore Courses for JEE exam

Similar JEE Doubts

Heat of reaction is the change in enthalpy or internal energy as represented by a balanced thermochemicalequation. The amount of energy released during a chemical change depends upon the state of reactantsand products, the conditions of pressure and volume at which reaction is carried out, and temperature.The variation of heat of reaction (ΔH or ΔE) with temperature is given as ΔH2 – ΔH1 = ΔCp [T2 – T1] or ΔE2– ΔE1 = ΔCv (T2 – T1). Standard heat enthalpy of elements in their most stable state is assumed to be zerowhereas standard heat enthalpy of compound is referred as heat of formation of that compound at 1 atmpressure and 25°C. Oxidation of N2 to N2O, NO, NO2 shows absorption of energy whereas heat of combustionof N2 is exothermic like other heat of combustion.Q. Heat of combustion of carbon in diamond and amorphous form are -94.3 and -97.6 kcal/mole. The heat required to convert 6 g carbon from diamond to amorphous form is

Heat of reaction is the change in enthalpy or internal energy as represented by a balanced thermochemicalequation. The amount of energy released during a chemical change depends upon the state of reactantsand products, the conditions of pressure and volume at which reaction is carried out, and temperature.The variation of heat of reaction (ΔH or ΔE) with temperature is given as ΔH2 – ΔH1 = ΔCp [T2 – T1] or ΔE2– ΔE1 = ΔCv (T2 – T1). Standard heat enthalpy of elements in their most stable state is assumed to be zerowhereas standard heat enthalpy of compound is referred as heat of formation of that compound at 1 atmpressure and 25°C. Oxidation of N2 to N2O, NO, NO2 shows absorption of energy whereas heat of combustionof N2 is exothermic like other heat of combustion.Q. Heat of vaporisation of H2O is 627.78 cal/g. If heat of formation of H2O(l)is -68.3 kcal, heat of formation of H2O(g)is

Top Courses for JEEView all

Top Courses for JEE

For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer?
Question Description
For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer?.
Solutions for For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice For the dissociation reaction,H2 (g) → 2H (g) ΔH = 162 Kcal,heat of atomisation of H isa)81 Kcalb)162 Kcalc)208 Kcald)218 KcalCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup