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16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron?
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16. A current of 2A passes through a coil of 350 turn wound on a ring ...
Calculation of Relative Permeability of Iron
Given:
Formula:
Solution:
Explanation:
Given:
- Current through coil, I = 2A
- Number of turns in coil, N = 350
- Mean diameter of ring, d = 12 cm
- Flux density in ring, B = 1.4 Wb/m²
Formula:
- Magnetic field intensity, H = (N * I) / l
- Magnetic field strength, B = μ * μo * H
- Flux density in ring, B = Φ / A
- Area of cross-section of ring, A = π * d² / 4
- Permeability of free space, μo = 4π * 10-7 H/m
- Relative permeability of iron, μ = B / (μo * H)
Solution:
- Length of ring, l = π * d = π * 12 cm = 37.7 cm = 0.377 m
- Magnetic field intensity, H = (350 * 2) / 0.377 = 1852.96 A/m
- Area of cross-section of ring, A = π * 12² / 4 = 113.1 cm² = 0.01131 m²
- Magnetic field strength, B = 1.4 * 10-3 T (1 T = 1 Wb/m²)
- Permeability of free space, μo = 4π * 10-7 H/m
- Relative permeability of iron, μ = B / (μo * H) = 1.4 * 10-3 / (4π * 10-7 * 1852.96) = 728.7
Explanation:
The given problem can be solved using the formula for magnetic field intensity, magnetic field strength, flux density, area of cross-section of the ring, permeability of free space, and relative permeability of iron. Firstly, we calculated the magnetic field intensity using the formula (N * I) / l. Then, we calculated the area of cross-section of the ring using the formula π * d² / 4. After that, we calculated the magnetic field strength using the formula μ * μo * H and flux density using the formula Φ / A. Later, we calculated the relative permeability of iron using the formula B / (μo * H). The relative permeability of iron is 728.7.
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16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron?
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16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron?.
16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about 16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 16. A current of 2A passes through a coil of 350 turn wound on a ring of mean diameter 12cm. The flux density established in the ring is 1.4 Wb/m2. Find the value of relative permeability of iron?.
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