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The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|
(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).
(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).
- a)[Co(H2O)6]2+
- b)[Cr(H2O)6]2+
- c)[Mn(H2O)6]2+
- d)[Fe(H2O)6]2+
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d ...
Electronic No. of unpaired configuration electrons
∴ Sin ce Co2+ ha s lowest no. of unpaired electrons hence lowest paramagnetic behaviour is shown by [Co(H2O)6]2+
∴ Sin ce Co2+ ha s lowest no. of unpaired electrons hence lowest paramagnetic behaviour is shown by [Co(H2O)6]2+
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The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d ...
Understanding Paramagnetism
Paramagnetic substances contain unpaired electrons, leading to magnetic behavior. The more unpaired electrons, the stronger the paramagnetic properties.
Electron Configurations
- Cr2+: d4 (4 unpaired electrons)
- Mn2+: d5 (5 unpaired electrons)
- Fe2+: d6 (4 unpaired electrons, depending on the ligand field)
- Co2+: d7 (3 unpaired electrons)
Analyzing Each Complex
- [Co(H2O)6]2+:
- d7 configuration.
- In an octahedral field, it has 3 unpaired electrons.
- Exhibits low paramagnetic behavior due to fewer unpaired electrons.
- [Cr(H2O)6]2+:
- d4 configuration.
- Has 4 unpaired electrons, leading to higher paramagnetism.
- [Mn(H2O)6]2+:
- d5 configuration.
- Features 5 unpaired electrons, resulting in strong paramagnetic behavior.
- [Fe(H2O)6]2+:
- d6 configuration.
- Depending on the ligand strength, it may have 4 or 2 unpaired electrons, but typically exhibits significant paramagnetic behavior.
Conclusion
Among the options, [Co(H2O)6]2+ has the lowest paramagnetic behavior due to its d7 configuration, which results in only 3 unpaired electrons. The other complexes exhibit more unpaired electrons leading to stronger paramagnetism. Thus, the correct answer is option 'A'.
Paramagnetic substances contain unpaired electrons, leading to magnetic behavior. The more unpaired electrons, the stronger the paramagnetic properties.
Electron Configurations
- Cr2+: d4 (4 unpaired electrons)
- Mn2+: d5 (5 unpaired electrons)
- Fe2+: d6 (4 unpaired electrons, depending on the ligand field)
- Co2+: d7 (3 unpaired electrons)
Analyzing Each Complex
- [Co(H2O)6]2+:
- d7 configuration.
- In an octahedral field, it has 3 unpaired electrons.
- Exhibits low paramagnetic behavior due to fewer unpaired electrons.
- [Cr(H2O)6]2+:
- d4 configuration.
- Has 4 unpaired electrons, leading to higher paramagnetism.
- [Mn(H2O)6]2+:
- d5 configuration.
- Features 5 unpaired electrons, resulting in strong paramagnetic behavior.
- [Fe(H2O)6]2+:
- d6 configuration.
- Depending on the ligand strength, it may have 4 or 2 unpaired electrons, but typically exhibits significant paramagnetic behavior.
Conclusion
Among the options, [Co(H2O)6]2+ has the lowest paramagnetic behavior due to its d7 configuration, which results in only 3 unpaired electrons. The other complexes exhibit more unpaired electrons leading to stronger paramagnetism. Thus, the correct answer is option 'A'.
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The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer?
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The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer?.
The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer?.
Solutions for The d-electron configurations of Cr2+, Mn2+, Fe2+ and Co2+ are d 4, d 5, d 6 and d 7 respectively.Which one of the following will exhibit the lowest paramagnetic behaviour?|(Atomic no. Cr = 24, Mn = 25, Fe = 26, Co = 27).a)[Co(H2O)6]2+b)[Cr(H2O)6]2+c)[Mn(H2O)6]2+d)[Fe(H2O)6]2+Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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