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Propene when treated with a cold cone. H2SO4 forms a compound which on heating with water gives
- a)propan-2-ol
- b)butan-1-ol
- c)ethanol
- d)propan-1-ol
Correct answer is option 'A'. Can you explain this answer?
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Propene when treated with a cold cone. H2SO4 forms a compound which o...
Propone when treated with cold cone. H2SO4 forms a compound, isopropyl* hydrogen sulphate on heating with water gives propan-2-ol.
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Propene when treated with a cold cone. H2SO4 forms a compound which o...
Formation of Propan-2-ol from Propene
Propan-2-ol is formed when propene is treated with a cold cone. H2SO4 followed by heating with water. Let's break down the reaction steps:
Step 1: Formation of Intermediate Compound
- When propene reacts with cold cone. H2SO4, an electrophilic addition reaction takes place. The H2SO4 acts as a catalyst and adds to the double bond of propene, forming an intermediate compound.
Step 2: Hydrolysis of Intermediate Compound
- The intermediate compound formed in Step 1 undergoes hydrolysis when heated with water. This hydrolysis reaction results in the formation of propan-2-ol.
Final Product: Propan-2-ol
Therefore, the compound obtained by treating propene with a cold cone. H2SO4 followed by heating with water is propan-2-ol (also known as isopropanol). This process involves the addition of water across the double bond of propene, leading to the formation of the alcohol propan-2-ol.
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Propene when treated with a cold cone. H2SO4 forms a compound which on heating with water givesa)propan-2-olb)butan-1-olc)ethanold)propan-1-olCorrect answer is option 'A'. Can you explain this answer?
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