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A 6 m-long vertical pole casts a shadow of 4 m. At the same time, a tower casts a shadow 25 m long on the ground. The height of the tower is :
  • a)
    45.5 m
  • b)
    40.5 m
  • c)
    37.5 m
  • d)
    32.5 m
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A 6 m-long vertical pole casts a shadow of 4 m. At the same time, a t...
Let the angle of elevation of the top of the tower from the endpoint of the shadow be
Then
∴ Height of the tower = 3/2 x 25 = 37.5 m
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Most Upvoted Answer
A 6 m-long vertical pole casts a shadow of 4 m. At the same time, a t...
To solve this problem, we can use the concept of similar triangles. Let's break down the solution step by step:

1. Let's consider the vertical pole and its shadow. We can create a right triangle with the pole as the height and the shadow as the base. Using the Pythagorean theorem, we can find the length of the hypotenuse (the distance from the top of the pole to the end of the shadow):

The length of the hypotenuse = √(height^2 + base^2)
= √(6^2 + 4^2)
= √(36 + 16)
= √52
= 2√13

2. Now, let's consider the tower and its shadow. We can create another right triangle with the height of the tower as the height and the shadow of the tower as the base. Using the same logic as before, we can find the length of the hypotenuse:

The length of the hypotenuse = √(height^2 + base^2)
= √(height^2 + 25^2)
= √(height^2 + 625)

3. Since the two triangles are similar, their corresponding sides are proportional. This means that the ratio of the height of the pole to the height of the tower is equal to the ratio of the length of the hypotenuse of the pole triangle to the length of the hypotenuse of the tower triangle:

height of pole / height of tower = length of hypotenuse of pole / length of hypotenuse of tower

6 / height of tower = 2√13 / √(height^2 + 625)

4. Cross-multiplying and simplifying the equation, we get:

6 * √(height^2 + 625) = 2√13 * height of tower

5. Squaring both sides of the equation to eliminate the square roots, we get:

36 * (height^2 + 625) = 4 * 13 * (height^2)

36 * height^2 + 22500 = 52 * height^2

16 * height^2 = 22500

height^2 = 22500 / 16

height^2 = 1406.25

height = √1406.25

height ≈ 37.5 m

Therefore, the height of the tower is approximately 37.5 m, which corresponds to option (c).
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A 6 m-long vertical pole casts a shadow of 4 m. At the same time, a tower casts a shadow 25 m long on the ground. The height of the tower is :a)45.5 mb)40.5 mc)37.5 md)32.5 mCorrect answer is option 'C'. Can you explain this answer?
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A 6 m-long vertical pole casts a shadow of 4 m. At the same time, a tower casts a shadow 25 m long on the ground. The height of the tower is :a)45.5 mb)40.5 mc)37.5 md)32.5 mCorrect answer is option 'C'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A 6 m-long vertical pole casts a shadow of 4 m. At the same time, a tower casts a shadow 25 m long on the ground. The height of the tower is :a)45.5 mb)40.5 mc)37.5 md)32.5 mCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 6 m-long vertical pole casts a shadow of 4 m. At the same time, a tower casts a shadow 25 m long on the ground. The height of the tower is :a)45.5 mb)40.5 mc)37.5 md)32.5 mCorrect answer is option 'C'. Can you explain this answer?.
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