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Train A crosses a stationery train B of equal length in 40 seconds, a bridge of length 1320 meters in 1 minute 40 seconds, travelling at the same speed. Find the length of train A.
- a)440 m
- b)330 m
- c)495 m
- d)Cannot be determined
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Train A crosses a stationery train B of equal length in 40 seconds, a...
Let the lengths of train A and train B be 's' meters.
View all questions of this test
Given that
To travel '2s' meters the train took 40 seconds.
Speed of the train =
To travel s + 1320 meters, it took 100 seconds.
Therefore s +1320 = 100 x 
Therefore 4s = 1320
Therefore s = 330 meters.
Most Upvoted Answer
Train A crosses a stationery train B of equal length in 40 seconds, a...
Given Data:
- Time taken to cross a stationary train B of equal length = 40 seconds
- Time taken to cross a bridge of length 1320 meters = 1 minute 40 seconds
Approach:
- Let the length of the train A be x meters.
- Speed of the train can be calculated as: Distance/Time
Calculations:
- When crossing the stationary train B:
Speed = Distance/Time
Speed = 2x/40 (as both trains are of equal length)
Speed = x/20
- When crossing the bridge:
Speed = Distance/Time
Speed = (x + 1320)/100 (as 1 minute 40 seconds = 100 seconds)
Speed = (x + 1320)/100
As the speed remains the same in both cases,
x/20 = (x + 1320)/100
100x = 20(x + 1320)
100x = 20x + 26400
80x = 26400
x = 330 meters
Conclusion:
Therefore, the length of train A is 330 meters. Hence, the correct option is (B) 330m.
- Time taken to cross a stationary train B of equal length = 40 seconds
- Time taken to cross a bridge of length 1320 meters = 1 minute 40 seconds
Approach:
- Let the length of the train A be x meters.
- Speed of the train can be calculated as: Distance/Time
Calculations:
- When crossing the stationary train B:
Speed = Distance/Time
Speed = 2x/40 (as both trains are of equal length)
Speed = x/20
- When crossing the bridge:
Speed = Distance/Time
Speed = (x + 1320)/100 (as 1 minute 40 seconds = 100 seconds)
Speed = (x + 1320)/100
As the speed remains the same in both cases,
x/20 = (x + 1320)/100
100x = 20(x + 1320)
100x = 20x + 26400
80x = 26400
x = 330 meters
Conclusion:
Therefore, the length of train A is 330 meters. Hence, the correct option is (B) 330m.
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Community Answer
Train A crosses a stationery train B of equal length in 40 seconds, a...
Let the lengths of train A and train B be 's' meters.
Given that
To travel '2s' meters the train took 40 seconds.
Speed of the train =
To travel s + 1320 meters, it took 100 seconds.
Therefore s +1320 = 100 x 
Therefore 4s = 1320
Therefore s = 330 meters.
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