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With 2's complement representation, the range of values that can be represented on the data bus of an 8 bit microprocessor is given by
  • a)
    -128 to 127
  • b)
    -128 to +128
  • c)
    -127 to 128
  • d)
    -256 to 256
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
With 2's complement representation, the range of values that can be re...
The 2's complement representation:
In 2's complement representation, the most significant bit (MSB) is the sign bit. If the sign bit is 0, the number is positive, and if the sign bit is 1, the number is negative. To obtain the 2's complement representation of a negative number, we invert all the bits and add 1 to the result.

Range of values representable on an 8-bit microprocessor:
An 8-bit microprocessor has 8 data lines, which means it can represent 2^8 = 256 different values. However, since the MSB is used as the sign bit, the range of values that can be represented is divided into two halves: positive values and negative values. The sign bit determines the sign of the number.

Explanation of the options:
a) -128 to 127: This option represents the correct range. The range of values from -128 to -1 represents the negative numbers, and the range from 0 to 127 represents the positive numbers. The total range is from -128 to 127, which includes 256 different values.
b) -128 to 128: This option is incorrect because it includes an extra positive value of 128, which is not possible with 8 bits. The range of positive values should only go up to 127.
c) -127 to 128: This option is incorrect because it excludes the negative value of -128. The range should include both the negative and positive values.
d) -256 to 256: This option is incorrect because it includes an extra negative value of -256, which is not possible with 8 bits. The range of negative values should only go down to -128.

Conclusion:
The correct range of values that can be represented on the data bus of an 8-bit microprocessor using 2's complement representation is -128 to 127. This range includes both negative and positive values, totaling 256 different values.
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With 2's complement representation, the range of values that can be represented on the data bus of an 8 bit microprocessor is given bya)-128 to 127b)-128 to +128c)-127 to 128d)-256 to 256Correct answer is option 'A'. Can you explain this answer?
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