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Consider the disk with following characteristics. Computer Network
• Transfer speed of 107 bytes/sec
• 10,000 RPM
• Average seek time of 8ms
• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.
Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?
ptions~
(a) 72
(b) 73
(c) 75
(d) 76
Correct answer is 'a'. Can you explain this answer?
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Consider the disk with following characteristics. Computer Network• T...
Time taken to transfer one HTML file
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= 
= 0.8 ms
= 0.8 msAvg. rotational latency = ½ x 6ms = 3 ms
[10,000 RPM ⇒1 rotation = 6 ms]
∴ Avg time to read an HTML file
= 0.8 + 3 ms + 8 ms + 2 ms = 13.8 ms
Time taken to read one HTML file = 13.8ms
1 sec ⇒ 1 sec 
= 72 files
= 72 files∴ 72 HTML files can read per second.
Most Upvoted Answer
Consider the disk with following characteristics. Computer Network• T...
Throughput to transfer HTML files:
To find the throughput to transfer HTML files, we need to consider the transfer speed, disk characteristics, and the system's maximum bandwidth.
Given:
Transfer speed = 107 bytes/sec
RPM = 10,000
Average seek time = 8ms
Overhead per disk operation = 2ms
System bus maximum bandwidth = 133 Megabytes/sec
Network connection bandwidth = 107 bytes/sec
HTML file size = 8000 bytes
Calculating throughput:
1. Calculate the disk transfer rate:
Disk transfer rate = (RPM / 60) * (bytes per track / average seek time)
We know that the disk transfer rate = 107 bytes/sec, and average seek time = 8ms.
Converting average seek time to seconds: 8ms = 0.008 seconds.
Therefore, (RPM / 60) * (bytes per track / 0.008) = 107 bytes/sec
Simplifying, bytes per track = (107 * 0.008 * 60) / RPM
2. Calculate the number of HTML files that can be transferred per second:
Number of HTML files per second = (disk transfer rate - overhead per disk operation) / HTML file size
We know that the overhead per disk operation = 2ms, which is equivalent to 0.002 seconds.
Therefore, (disk transfer rate - 0.002) / 8000 = throughput in HTML files per second
3. Calculate the maximum throughput:
Since the system bus has a maximum bandwidth of 133 Megabytes/sec, we need to convert it to bytes/sec:
133 Megabytes/sec = 133 * 1024 * 1024 bytes/sec
Now, we can substitute the calculated disk transfer rate and HTML file size into the formula:
(disk transfer rate - 0.002) / 8000 = 133 * 1024 * 1024
Solving this equation will give us the maximum throughput in HTML files per second.
Answer:
The correct answer is option (a) 72.
To find the throughput to transfer HTML files, we need to consider the transfer speed, disk characteristics, and the system's maximum bandwidth.
Given:
Transfer speed = 107 bytes/sec
RPM = 10,000
Average seek time = 8ms
Overhead per disk operation = 2ms
System bus maximum bandwidth = 133 Megabytes/sec
Network connection bandwidth = 107 bytes/sec
HTML file size = 8000 bytes
Calculating throughput:
1. Calculate the disk transfer rate:
Disk transfer rate = (RPM / 60) * (bytes per track / average seek time)
We know that the disk transfer rate = 107 bytes/sec, and average seek time = 8ms.
Converting average seek time to seconds: 8ms = 0.008 seconds.
Therefore, (RPM / 60) * (bytes per track / 0.008) = 107 bytes/sec
Simplifying, bytes per track = (107 * 0.008 * 60) / RPM
2. Calculate the number of HTML files that can be transferred per second:
Number of HTML files per second = (disk transfer rate - overhead per disk operation) / HTML file size
We know that the overhead per disk operation = 2ms, which is equivalent to 0.002 seconds.
Therefore, (disk transfer rate - 0.002) / 8000 = throughput in HTML files per second
3. Calculate the maximum throughput:
Since the system bus has a maximum bandwidth of 133 Megabytes/sec, we need to convert it to bytes/sec:
133 Megabytes/sec = 133 * 1024 * 1024 bytes/sec
Now, we can substitute the calculated disk transfer rate and HTML file size into the formula:
(disk transfer rate - 0.002) / 8000 = 133 * 1024 * 1024
Solving this equation will give us the maximum throughput in HTML files per second.
Answer:
The correct answer is option (a) 72.
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Consider the disk with following characteristics. Computer Network• Transfer speed of 107 bytes/sec• 10,000 RPM• Average seek time of 8ms• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?ptions~(a) 72(b) 73(c) 75(d) 76Correct answer is 'a'. Can you explain this answer?
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Consider the disk with following characteristics. Computer Network• Transfer speed of 107 bytes/sec• 10,000 RPM• Average seek time of 8ms• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?ptions~(a) 72(b) 73(c) 75(d) 76Correct answer is 'a'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider the disk with following characteristics. Computer Network• Transfer speed of 107 bytes/sec• 10,000 RPM• Average seek time of 8ms• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?ptions~(a) 72(b) 73(c) 75(d) 76Correct answer is 'a'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the disk with following characteristics. Computer Network• Transfer speed of 107 bytes/sec• 10,000 RPM• Average seek time of 8ms• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?ptions~(a) 72(b) 73(c) 75(d) 76Correct answer is 'a'. Can you explain this answer?.
Consider the disk with following characteristics. Computer Network• Transfer speed of 107 bytes/sec• 10,000 RPM• Average seek time of 8ms• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?ptions~(a) 72(b) 73(c) 75(d) 76Correct answer is 'a'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Consider the disk with following characteristics. Computer Network• Transfer speed of 107 bytes/sec• 10,000 RPM• Average seek time of 8ms• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?ptions~(a) 72(b) 73(c) 75(d) 76Correct answer is 'a'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the disk with following characteristics. Computer Network• Transfer speed of 107 bytes/sec• 10,000 RPM• Average seek time of 8ms• Each disk operation has 2 ms overhead, Assume system bus has a maximum bandwidth of 133 Megabytes per second and network connection has bandwidth of 107 bytes/sec. HTML files have an average of 8000 bytes. Each HTML file occupied one sector.Find the throughput to transfer HTML files? (Round to nearest integer). Assume throughput is the number of HTML files read per second?ptions~(a) 72(b) 73(c) 75(d) 76Correct answer is 'a'. Can you explain this answer?.
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