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A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio is
- a)76
- b)77
Correct answer is between '76,77'. Can you explain this answer?
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Verified Answer
A super heterodyne receiver having RF amplifier is tuned to 1200 kHz,...
a = Image rejection ratio 
[Turned circuit of same quality factor used ar two stages]
Therefore,
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A super heterodyne receiver having RF amplifier is tuned to 1200 kHz,...
Solution:
Given data:
- Tuned frequency of RF amplifier = 1200 kHz
- Intermediate frequency (IF) = 450 kHz
- Quality factor of tuned circuit at RF amplifier and mixer = Q = 65
We know that the image frequency is given by:
f_image = 2 × f_IF - f_RF
where f_RF is the tuned frequency of the RF amplifier.
Substituting the given values, we get:
f_image = 2 × 450 kHz - 1200 kHz = -300 kHz
The negative sign indicates that the image frequency is below the RF frequency.
The bandwidth of the tuned circuit is given by:
BW = f_RF / Q
At RF amplifier, the bandwidth is:
BW_RF = 1200 kHz / 65 = 18.46 kHz
At mixer, the bandwidth is:
BW_mixer = 450 kHz / 65 = 6.92 kHz
The image rejection ratio (IRR) is given by:
IRR = BW_RF / BW_mixer
Substituting the values, we get:
IRR = 18.46 kHz / 6.92 kHz = 2.67
Multiplying by 20 in decibels, we get:
IRR (dB) = 20 log (IRR) = 20 log (2.67) = 7.6 dB
Therefore, the image rejection ratio is between 76 dB and 77 dB (rounded off to the nearest integer).
Given data:
- Tuned frequency of RF amplifier = 1200 kHz
- Intermediate frequency (IF) = 450 kHz
- Quality factor of tuned circuit at RF amplifier and mixer = Q = 65
We know that the image frequency is given by:
f_image = 2 × f_IF - f_RF
where f_RF is the tuned frequency of the RF amplifier.
Substituting the given values, we get:
f_image = 2 × 450 kHz - 1200 kHz = -300 kHz
The negative sign indicates that the image frequency is below the RF frequency.
The bandwidth of the tuned circuit is given by:
BW = f_RF / Q
At RF amplifier, the bandwidth is:
BW_RF = 1200 kHz / 65 = 18.46 kHz
At mixer, the bandwidth is:
BW_mixer = 450 kHz / 65 = 6.92 kHz
The image rejection ratio (IRR) is given by:
IRR = BW_RF / BW_mixer
Substituting the values, we get:
IRR = 18.46 kHz / 6.92 kHz = 2.67
Multiplying by 20 in decibels, we get:
IRR (dB) = 20 log (IRR) = 20 log (2.67) = 7.6 dB
Therefore, the image rejection ratio is between 76 dB and 77 dB (rounded off to the nearest integer).
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A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio isa)76b)77Correct answer is between '76,77'. Can you explain this answer?
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A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio isa)76b)77Correct answer is between '76,77'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio isa)76b)77Correct answer is between '76,77'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio isa)76b)77Correct answer is between '76,77'. Can you explain this answer?.
A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio isa)76b)77Correct answer is between '76,77'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio isa)76b)77Correct answer is between '76,77'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A super heterodyne receiver having RF amplifier is tuned to 1200 kHz, the intermediate frequency is 450 kHz. The quality factor of the tuned circuit at RF amplifier and at the mixer are same and is equal to 65. The image rejection ratio isa)76b)77Correct answer is between '76,77'. Can you explain this answer?.
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