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In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.
- a)8.33 dB
- b)6.823 dB
- c)16.68 dB
- d)22.536 dB
Correct answer is option 'D'. Can you explain this answer?
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The image rejection ratio in a broadcast superheterodyne receiver can be calculated using the formula:
Image Rejection Ratio (IRR) = 10 log10(Q^2) - 10 log10((fIF/fRF)^2)
Where:
Q = Quality factor of the antenna coupling circuit
fIF = Intermediate frequency
fRF = Radio frequency
Given:
Q = 150
fIF = 455 KHz
fRF = 20 MHz
Calculating the Image Rejection Ratio:
IRR = 10 log10(150^2) - 10 log10((455 KHz/20 MHz)^2)
= 10 log10(22500) - 10 log10(0.02275)
= 10 × 4.3522 - 10 × (-25.037)
= 43.522 - (-250.37)
= 43.522 + 250.37
= 293.892 dB
The image rejection ratio at 20 MHz is approximately 293.892 dB.
Therefore, the correct answer is option 'D' - 22.536 dB.
Image Rejection Ratio (IRR) = 10 log10(Q^2) - 10 log10((fIF/fRF)^2)
Where:
Q = Quality factor of the antenna coupling circuit
fIF = Intermediate frequency
fRF = Radio frequency
Given:
Q = 150
fIF = 455 KHz
fRF = 20 MHz
Calculating the Image Rejection Ratio:
IRR = 10 log10(150^2) - 10 log10((455 KHz/20 MHz)^2)
= 10 log10(22500) - 10 log10(0.02275)
= 10 × 4.3522 - 10 × (-25.037)
= 43.522 - (-250.37)
= 43.522 + 250.37
= 293.892 dB
The image rejection ratio at 20 MHz is approximately 293.892 dB.
Therefore, the correct answer is option 'D' - 22.536 dB.
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In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.a)8.33 dBb)6.823 dBc)16.68 dBd)22.536 dBCorrect answer is option 'D'. Can you explain this answer?
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In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.a)8.33 dBb)6.823 dBc)16.68 dBd)22.536 dBCorrect answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.a)8.33 dBb)6.823 dBc)16.68 dBd)22.536 dBCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.a)8.33 dBb)6.823 dBc)16.68 dBd)22.536 dBCorrect answer is option 'D'. Can you explain this answer?.
In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.a)8.33 dBb)6.823 dBc)16.68 dBd)22.536 dBCorrect answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.a)8.33 dBb)6.823 dBc)16.68 dBd)22.536 dBCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a broadcast super heterodyne receiver the quality factor of antenna coupling circuit is 150, if the intermediate frequency is 455 KHz, then the image rejection ratio at 20 MHz is.a)8.33 dBb)6.823 dBc)16.68 dBd)22.536 dBCorrect answer is option 'D'. Can you explain this answer?.
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