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The intermediate frequency of an AM superheterodyne receiver is 460kHz and the local oscillator frequency {fLO) of the mixer is set at the higher of the two possible values, such that fLO > fc always. If the carries frequency {fC of the receiver signal is 700kHz, then the carrier frequency of the corresponding image signal will be kHz
- a)1620 kHz.
- b)1621 kHz.
- c)1622 kHz.
- d)None of these.
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The intermediate frequency of an AM superheterodyne receiver is 460kHz...
Given that fc = 700 kHz
fIF - 460 kHz and fLO > fc
So, the carrier frequency of the corresponding image signal can be given as
Most Upvoted Answer
The intermediate frequency of an AM superheterodyne receiver is 460kHz...
= 460kHz + 10.7MHz = 11.16MHz.
Explanation:
In an AM superheterodyne receiver, the incoming radio signal is mixed with a local oscillator signal to produce an intermediate frequency (IF) signal that is easier to amplify and demodulate. The IF frequency is typically a fixed value, and in this case, it is given as 460kHz.
The local oscillator frequency is the frequency of the signal that is mixed with the incoming radio signal. The local oscillator frequency can be set at one of two possible values such that the resulting IF frequency is equal to the fixed IF frequency of the receiver. These two values are given by:
fLO = fRF ± fIF
where fRF is the frequency of the incoming radio signal and fIF is the fixed IF frequency of the receiver.
In this case, we know that fIF = 460kHz. We also know that the local oscillator frequency is set at the higher of the two possible values. This means that fLO = fRF + fIF. Solving for fLO, we get:
fLO = fRF + fIF
fRF = fLO - fIF
fRF = 11.16MHz - 460kHz
fRF = 10.7MHz
Therefore, the local oscillator frequency is set at 11.16MHz, and the frequency of the incoming radio signal is 10.7MHz.
Explanation:
In an AM superheterodyne receiver, the incoming radio signal is mixed with a local oscillator signal to produce an intermediate frequency (IF) signal that is easier to amplify and demodulate. The IF frequency is typically a fixed value, and in this case, it is given as 460kHz.
The local oscillator frequency is the frequency of the signal that is mixed with the incoming radio signal. The local oscillator frequency can be set at one of two possible values such that the resulting IF frequency is equal to the fixed IF frequency of the receiver. These two values are given by:
fLO = fRF ± fIF
where fRF is the frequency of the incoming radio signal and fIF is the fixed IF frequency of the receiver.
In this case, we know that fIF = 460kHz. We also know that the local oscillator frequency is set at the higher of the two possible values. This means that fLO = fRF + fIF. Solving for fLO, we get:
fLO = fRF + fIF
fRF = fLO - fIF
fRF = 11.16MHz - 460kHz
fRF = 10.7MHz
Therefore, the local oscillator frequency is set at 11.16MHz, and the frequency of the incoming radio signal is 10.7MHz.
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The intermediate frequency of an AM superheterodyne receiver is 460kHz and the local oscillator frequency {fLO) of the mixer is set at the higher of the two possible values, such that fLO > fc always. If the carries frequency {fC of the receiver signal is 700kHz, then the carrier frequency of the corresponding image signal will be kHza)1620 kHz.b)1621 kHz.c)1622 kHz.d)None of these.Correct answer is option 'A'. Can you explain this answer?
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