Question Description
A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer?.

Solutions for A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A circular coil of 70 turns and radius 5 cm carrying a current of 8 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.5 T. The field lines make an angle of 30o with the normal of the coil then the magnitude of the counter torque that must be applied to prevent the coil from turning isa)33 Nmb)3.3 Nmc)3.3×10−2Nmd)3.3×10−4NmCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.