NEET Exam > NEET Questions > An electron is moving in a cyclotron at a spe...
Start Learning for Free
An electron is moving in a cyclotron at a speed of 3.2 x 107 m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?
(q = 1.6 x 10-19 C, me = 9.1 x 10-31 kg)
(q = 1.6 x 10-19 C, me = 9.1 x 10-31 kg)
- a)1.4 x 105 Hz
- b)1.4 x 107 Hz
- c)1.4 x 106 Hz
- d)1.4 x 109 Hz
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a...
v = 3.2 x 107 m s-1 ;B = 5 x 10-4 T
The frequency of electron is
The frequency of electron is
Free Test
FREE
| Start Free Test |
Community Answer
An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a...
To find the frequency of the electron, we can use the equation for the cyclotron frequency:
f = qB / (2πm)
where:
f is the frequency of the electron
q is the charge of the electron (1.6 x 10^(-19) C)
B is the magnetic field (5 x 10^(-4) T)
m is the mass of the electron (9.1 x 10^(-31) kg)
Let's plug in the given values and solve for f.
Calculation:
f = (1.6 x 10^(-19) C) * (5 x 10^(-4) T) / (2π * 9.1 x 10^(-31) kg)
Using the given values, we can substitute the values into the equation:
f = (1.6 x 5) / (2π * 9.1) * (10^(-19) * 10^(-4)) / (10^(-31))
Simplifying the equation:
f = 8 / (2π * 9.1) * (10^(-19-4) / 10^(-31))
f = 8 / (2π * 9.1) * 10^(-23)
f = 8 * 10^(-23) / (2π * 9.1)
f ≈ 1.4 x 10^(-23) / 57
f ≈ 2.46 x 10^(-25)
Therefore, the frequency of the electron is approximately 2.46 x 10^(-25) Hz.
The correct answer is not listed in the options provided. Please double-check the given options or provide the correct answer.
f = qB / (2πm)
where:
f is the frequency of the electron
q is the charge of the electron (1.6 x 10^(-19) C)
B is the magnetic field (5 x 10^(-4) T)
m is the mass of the electron (9.1 x 10^(-31) kg)
Let's plug in the given values and solve for f.
Calculation:
f = (1.6 x 10^(-19) C) * (5 x 10^(-4) T) / (2π * 9.1 x 10^(-31) kg)
Using the given values, we can substitute the values into the equation:
f = (1.6 x 5) / (2π * 9.1) * (10^(-19) * 10^(-4)) / (10^(-31))
Simplifying the equation:
f = 8 / (2π * 9.1) * (10^(-19-4) / 10^(-31))
f = 8 / (2π * 9.1) * 10^(-23)
f = 8 * 10^(-23) / (2π * 9.1)
f ≈ 1.4 x 10^(-23) / 57
f ≈ 2.46 x 10^(-25)
Therefore, the frequency of the electron is approximately 2.46 x 10^(-25) Hz.
The correct answer is not listed in the options provided. Please double-check the given options or provide the correct answer.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer?
Question Description
An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer?.
An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer?.
Solutions for An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An electron is moving in a cyclotron at a speed of 3.2 x 107m s-1 in a magnetic field of 5 x 10-4 T perpendicular to it. What is the frequency of this electron?(q = 1.6 x 10-19C, me= 9.1 x 10-31kg)a)1.4 x 105Hzb)1.4 x 107Hzc)1.4 x 106Hzd)1.4 x 109HzCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup