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Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?
- a)494.5 x 10-6 J/atom
- b)8169.5 x 10-10 J/atom
- c)5.85 x 10-15 J/atom
- d)8.214 x 10-19 J/atom
Correct answer is option 'D'. Can you explain this answer?
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**Answer:**
The ionisation energy of an atom is the minimum amount of energy required to remove an electron from the atom in its ground state and produce a positively charged ion. In other words, it is the energy required to break the bond between the electron and the nucleus.
To calculate the ionisation energy of sodium per atom, we can use the equation:
\[E = hc/\lambda\]
where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the electromagnetic radiation.
Given that the wavelength (λ) is 242 nm, we need to convert it to meters:
\[λ = 242 \times 10^{-9} \, \text{m}\]
We can then substitute the values into the equation:
\[E = (6.62607004 \times 10^{-34} \, \text{J s} \times 3.00 \times 10^8 \, \text{m/s}) / (242 \times 10^{-9} \, \text{m})\]
Simplifying the equation:
\[E = 8.214 \times 10^{-19} \, \text{J}\]
Therefore, the ionisation energy of sodium per atom is 8.214 x 10^-19 J/atom, which corresponds to option D.
The ionisation energy of an atom is the minimum amount of energy required to remove an electron from the atom in its ground state and produce a positively charged ion. In other words, it is the energy required to break the bond between the electron and the nucleus.
To calculate the ionisation energy of sodium per atom, we can use the equation:
\[E = hc/\lambda\]
where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength of the electromagnetic radiation.
Given that the wavelength (λ) is 242 nm, we need to convert it to meters:
\[λ = 242 \times 10^{-9} \, \text{m}\]
We can then substitute the values into the equation:
\[E = (6.62607004 \times 10^{-34} \, \text{J s} \times 3.00 \times 10^8 \, \text{m/s}) / (242 \times 10^{-9} \, \text{m})\]
Simplifying the equation:
\[E = 8.214 \times 10^{-19} \, \text{J}\]
Therefore, the ionisation energy of sodium per atom is 8.214 x 10^-19 J/atom, which corresponds to option D.
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Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer?
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Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer?.
Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer?.
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Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Electromagnetic radiation of wavelength 242 nm is just sufficient to ionise the sodium atom. What is the ionisation energy of sodium per atom?a)494.5 x 10-6 J/atomb)8169.5 x 10-10 J/atomc)5.85 x 10-15 J/atomd)8.214 x 10-19 J/atomCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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