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A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer?.

Solutions for A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the center of the magnet. Calculate the horizontal component of earth’s magnetic field.a)0.12 × 10–4 Tb)0.21× 10–4 Tc)0.34 × 10–4 Td)0.87 × 10–7 TCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.