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A magnet 10 cm long and having a pole strength 2 A-m is deflected through 30º from the magnetic meridian. The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple is
- a)32 x 10 -7 N-m
- b)16 x 10-7 N-m
- c)64 x 10 -7 N-m
- d)48 x 10-7 N-m
Correct answer is option 'A'. Can you explain this answer?
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A magnet 10 cm long and having a pole strength 2 A-mis deflected throu...
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A magnet 10 cm long and having a pole strength 2 A-mis deflected throu...
In order to calculate the deflection of a magnet, we need to know the magnetic field strength it is experiencing. Without this information, we cannot accurately determine the deflection angle.
However, if we assume that the magnet is being deflected due to the presence of another magnetic field, we can use the formula for the torque experienced by a magnetic dipole in a magnetic field to calculate the deflection angle.
The formula for the torque experienced by a magnetic dipole is:
τ = m × B × sin(θ)
Where:
τ is the torque
m is the magnetic dipole moment
B is the magnetic field strength
θ is the angle between the dipole moment and the magnetic field
Given:
Length of the magnet (l) = 10 cm = 0.1 m
Pole strength (magnetic dipole moment) (m) = 2 A-m
Assuming the magnet is deflected through an angle (θ) of 30 degrees, we can rearrange the formula to solve for the magnetic field strength (B):
τ = m × B × sin(θ)
B = τ / (m × sin(θ))
Let's assume the torque (τ) is 1 N-m. Plugging in the values:
B = 1 N-m / (2 A-m × sin(30°))
B = 1 N-m / (2 A-m × 0.5)
B = 1 N-m / 1 A-m
B = 1 T
Therefore, if the magnet is deflected through an angle of 30 degrees with a torque of 1 N-m, the magnetic field strength it is experiencing is 1 Tesla.
However, if we assume that the magnet is being deflected due to the presence of another magnetic field, we can use the formula for the torque experienced by a magnetic dipole in a magnetic field to calculate the deflection angle.
The formula for the torque experienced by a magnetic dipole is:
τ = m × B × sin(θ)
Where:
τ is the torque
m is the magnetic dipole moment
B is the magnetic field strength
θ is the angle between the dipole moment and the magnetic field
Given:
Length of the magnet (l) = 10 cm = 0.1 m
Pole strength (magnetic dipole moment) (m) = 2 A-m
Assuming the magnet is deflected through an angle (θ) of 30 degrees, we can rearrange the formula to solve for the magnetic field strength (B):
τ = m × B × sin(θ)
B = τ / (m × sin(θ))
Let's assume the torque (τ) is 1 N-m. Plugging in the values:
B = 1 N-m / (2 A-m × sin(30°))
B = 1 N-m / (2 A-m × 0.5)
B = 1 N-m / 1 A-m
B = 1 T
Therefore, if the magnet is deflected through an angle of 30 degrees with a torque of 1 N-m, the magnetic field strength it is experiencing is 1 Tesla.
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A magnet 10 cm long and having a pole strength 2 A-mis deflected through 30ºfrom the magnetic meridian.The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple isa)32 x 10 -7 N-mb)16 x 10-7 N-mc)64 x 10 -7 N-md)48 x 10-7 N-mCorrect answer is option 'A'. Can you explain this answer?
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A magnet 10 cm long and having a pole strength 2 A-mis deflected through 30ºfrom the magnetic meridian.The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple isa)32 x 10 -7 N-mb)16 x 10-7 N-mc)64 x 10 -7 N-md)48 x 10-7 N-mCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A magnet 10 cm long and having a pole strength 2 A-mis deflected through 30ºfrom the magnetic meridian.The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple isa)32 x 10 -7 N-mb)16 x 10-7 N-mc)64 x 10 -7 N-md)48 x 10-7 N-mCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A magnet 10 cm long and having a pole strength 2 A-mis deflected through 30ºfrom the magnetic meridian.The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple isa)32 x 10 -7 N-mb)16 x 10-7 N-mc)64 x 10 -7 N-md)48 x 10-7 N-mCorrect answer is option 'A'. Can you explain this answer?.
A magnet 10 cm long and having a pole strength 2 A-mis deflected through 30ºfrom the magnetic meridian.The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple isa)32 x 10 -7 N-mb)16 x 10-7 N-mc)64 x 10 -7 N-md)48 x 10-7 N-mCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A magnet 10 cm long and having a pole strength 2 A-mis deflected through 30ºfrom the magnetic meridian.The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple isa)32 x 10 -7 N-mb)16 x 10-7 N-mc)64 x 10 -7 N-md)48 x 10-7 N-mCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A magnet 10 cm long and having a pole strength 2 A-mis deflected through 30ºfrom the magnetic meridian.The horizontal component of earth’s induction is 0.32 x 10 -4T then the value of deflecting couple isa)32 x 10 -7 N-mb)16 x 10-7 N-mc)64 x 10 -7 N-md)48 x 10-7 N-mCorrect answer is option 'A'. Can you explain this answer?.
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