If m and n are nonzero integers, is m/n an integer?1) 2m is divisible ...
Statement 1: 2m is divisible by n
If 2m is divisible by n, it means that n is a factor of 2m. However, since m and n are both nonzero integers, this does not necessarily mean that m/n is an integer. For example, let's consider the case where m = 3 and n = 4. In this case, 2m = 6, which is divisible by n = 4. However, m/n = 3/4, which is not an integer. Therefore, statement 1 alone is not sufficient to determine whether m/n is an integer.
Statement 2: m is divisible by 2n
If m is divisible by 2n, it means that 2n is a factor of m. Similar to statement 1, this does not guarantee that m/n is an integer. For example, let's consider the case where m = 8 and n = 2. In this case, 2n = 4, which is a factor of m = 8. However, m/n = 8/2 = 4, which is an integer. Therefore, statement 2 alone is sufficient to determine that m/n is an integer.
Combined:
When we consider both statements together, we can see that both 2m is divisible by n and m is divisible by 2n. This means that both n is a factor of 2m and 2n is a factor of m.
If n is a factor of 2m and 2n is a factor of m, it implies that m/n is an integer. This is because the factors of m (2n) completely cancel out with the factors of n (2m), leaving no remainder.
Therefore, statement 2 alone is sufficient to determine that m/n is an integer. However, statement 1 alone is not sufficient.
Hence, the correct answer is option A: Exactly one of the statements can answer the question.
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