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An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency?
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An electron in an atom drops from an energy leveal at -1.1×10-18 J to ...
Calculating the frequency of the emitted photon
To calculate the frequency of the emitted photon, we can use the equation:
ΔE = hf
Where ΔE is the change in energy, h is Planck's constant, and f is the frequency of the emitted photon.
Calculating the change in energy
The change in energy can be calculated by subtracting the final energy level from the initial energy level:
ΔE = -2.4×10^-18 J - (-1.1×10^-18 J)
ΔE = -1.3×10^-18 J
Calculating the frequency
Now that we know the change in energy, we can use the equation above to calculate the frequency:
-1.3×10^-18 J = hf
f = (-1.3×10^-18 J) / h
We can look up the value of Planck's constant, which is approximately 6.626×10^-34 J s:
f = (-1.3×10^-18 J) / (6.626×10^-34 J s)
f = 1.96×10^15 Hz
Therefore, the frequency of the emitted photon is 1.96×10^15 Hz.
Explanation
When an electron in an atom drops from a higher energy level to a lower energy level, it releases energy in the form of a photon. The energy of the photon is equal to the energy difference between the two levels. The frequency of the photon is related to its energy through Planck's equation. By calculating the change in energy and using Planck's equation, we can determine the frequency of the emitted photon.
To calculate the frequency of the emitted photon, we can use the equation:
ΔE = hf
Where ΔE is the change in energy, h is Planck's constant, and f is the frequency of the emitted photon.
Calculating the change in energy
The change in energy can be calculated by subtracting the final energy level from the initial energy level:
ΔE = -2.4×10^-18 J - (-1.1×10^-18 J)
ΔE = -1.3×10^-18 J
Calculating the frequency
Now that we know the change in energy, we can use the equation above to calculate the frequency:
-1.3×10^-18 J = hf
f = (-1.3×10^-18 J) / h
We can look up the value of Planck's constant, which is approximately 6.626×10^-34 J s:
f = (-1.3×10^-18 J) / (6.626×10^-34 J s)
f = 1.96×10^15 Hz
Therefore, the frequency of the emitted photon is 1.96×10^15 Hz.
Explanation
When an electron in an atom drops from a higher energy level to a lower energy level, it releases energy in the form of a photon. The energy of the photon is equal to the energy difference between the two levels. The frequency of the photon is related to its energy through Planck's equation. By calculating the change in energy and using Planck's equation, we can determine the frequency of the emitted photon.
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An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency?
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An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency?.
An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An electron in an atom drops from an energy leveal at -1.1×10-18 J to an energy level at -2.4×10-18 J. The wave associated with the emitted photon has a frequency?.
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