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Compare two characteristics of an equal number of individuals using measures of variability. You will interview two sets of five (5) different students online.?
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Compare two characteristics of an equal number of individuals using me...
Introduction
In this activity, we will compare two characteristics of two groups of five students each. We'll focus on their heights and exam scores, using measures of variability to analyze the differences.
Group A: Heights
- Heights of Students:
- Student 1: 150 cm
- Student 2: 155 cm
- Student 3: 160 cm
- Student 4: 158 cm
- Student 5: 162 cm
- Calculate Variability:
- Mean Height: (150 + 155 + 160 + 158 + 162) / 5 = 157 cm
- Range: 162 cm - 150 cm = 12 cm
- Standard Deviation: A measure of how spread out the heights are around the mean.
Group B: Exam Scores
- Exam Scores of Students:
- Student 1: 78
- Student 2: 85
- Student 3: 90
- Student 4: 88
- Student 5: 92
- Calculate Variability:
- Mean Score: (78 + 85 + 90 + 88 + 92) / 5 = 86.6
- Range: 92 - 78 = 14
- Standard Deviation: Indicates how scores vary from the average score.
Comparison of Variability
- Height Variability:
- Height Range: 12 cm indicates a moderate spread among the heights of Group A students.
- Score Variability:
- Score Range: 14 points shows a slightly wider spread in the exam scores of Group B.
Conclusion
By comparing the variability of heights and exam scores, we can see that both groups exhibit a similar level of spread, but the range in exam scores is slightly higher. This indicates that while heights are relatively consistent, the exam scores show a broader variation among the students.
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Compare two characteristics of an equal number of individuals using measures of variability. You will interview two sets of five (5) different students online.?
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