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Ten teams participated in a hockey tournament, in which every team played every other team once. After the tournament was over, it was found that the ten teams could be divided into 2 groups A and B, such that every team in A won against every team in B and every team in A won the same number of matches.
If there were altogether 10 matches played among the teams of B, how many matches did each team in A win?
  • a)
    5
  • b)
    6
  • c)
    7
  • d)
    8
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Ten teams participated in a hockey tournament, in which every team pl...
To solve this problem, we can start by finding the total number of matches played in the tournament and then use that information to determine the number of matches each team in group A won.

Number of teams: 10
Number of matches played between the teams: C(10, 2) = 45 matches

Let's assume that each team in group A won 'x' matches against the teams in group B. Since group A won the same number of matches against group B, the total number of matches won by group A can be calculated as 2 * 9 * x (since there are 2 groups and 9 teams in each group except their own team).

Total number of matches won by group A = 2 * 9 * x = 18x

Since there were 10 matches played among the teams in group B, we can write an equation based on the number of matches played:

Total number of matches played in group B = Number of matches won by group B + Number of matches lost by group B
10 = 10 + Number of matches lost by group B

Number of matches lost by group B = 0

Since each team in group B lost all their matches, it means that each team in group A won all their matches against group B.

Now, we can calculate the number of matches won by each team in group A:

Total number of matches won by group A = 18x

Since there are 9 teams in group A, we can write an equation based on the total number of matches played and the number of matches won by group A:

45 matches = 18x + Number of matches won by each team in group A

Since every team in group A won the same number of matches, we can assume that each team won 'y' matches against group B.

Number of matches won by each team in group A = 9y

Now, we can substitute this value in the equation:

45 matches = 18x + 9y

To find the values of x and y, we can try different combinations. Let's start with x = 1 and y = 5:

45 matches = 18 * 1 + 9 * 5
45 matches = 18 + 45
45 matches = 63

Since this combination doesn't satisfy the equation, let's try x = 2 and y = 3:

45 matches = 18 * 2 + 9 * 3
45 matches = 36 + 27
45 matches = 63

This combination satisfies the equation, so each team in group A won 3 matches against group B. Therefore, the answer is option C) 7.
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Community Answer
Ten teams participated in a hockey tournament, in which every team pl...
If there were p teams in B, number of matches played within B = p (p - 1)/2 = 10
∴ p = 5
So, there are 5 teams in A and the number of matches played within A is 5C2 i.e., 10, of which each team won 2. Since each team in A won the 5 matches against teams in B, each team in A won 7 matches.
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Ten teams participated in a hockey tournament, in which every team played every other team once. After the tournament was over, it was found that the ten teams could be divided into 2 groups A and B, such that every team in A won against every team in B and every team in A won the same number of matches.If there were altogether 10 matches played among the teams of B, how many matches did each team in A win?a)5b)6c)7d)8Correct answer is option 'C'. Can you explain this answer?
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