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One litre of 1 M CuSO4 solution is electrolysed.
After passing 2 F of electricity, molarity of CuSO4 solution will be
  • a)
    M/2
  • b)
    M/4
  • c)
    M
  • d)
    0
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
One litre of 1 M CuSO4 solution is electrolysed.After passing 2 F of ...

Explanation:

Given:
- Initial molarity of CuSO4 solution = 1 M
- Charge passed = 2 F

Electrolysis of CuSO4:
- When 1 F of electricity is passed through 1 M CuSO4 solution, 1 mole of Cu is deposited.
- Therefore, when 2 F of electricity is passed, 2 moles of Cu will be deposited.

Calculation:
- The formula weight of Cu is 63.5 g/mol.
- So, 2 moles of Cu will be 127 g.
- Since 1 litre of 1 M CuSO4 solution contains 63.5 g of CuSO4, the solution will be completely consumed after deposition of 127 g of Cu.
- This means the final molarity of CuSO4 solution will be 0.

Therefore, after passing 2 F of electricity, the molarity of CuSO4 solution will be 0.
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Community Answer
One litre of 1 M CuSO4 solution is electrolysed.After passing 2 F of ...
1 L of 1M CuSO4 = 1 mol of Cu2+
Cu2+ + 2e- → Cu
2 F of electricity will convert dil Cu2+ into Cu, hence [CuSO4] = 0
Thus, (d)
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One litre of 1 M CuSO4 solution is electrolysed.After passing 2 F of electricity, molarity of CuSO4 solution will bea)M/2b)M/4c)Md)0Correct answer is option 'D'. Can you explain this answer?
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