Class 10 Exam > Class 10 Questions > If 09/12/2001 happens to be Sunday, then 09/1...
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If 09/12/2001 happens to be Sunday, then 09/12/1971 would have been at
- a)Wednesday
- b)Tuesday
- c)Saturday
- d)Thursday
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
If 09/12/2001 happens to be Sunday, then 09/12/1971 would have been at...
Calculation
To determine the day of the week for 09/12/1971, we need to calculate the number of days between 09/12/1971 and 09/12/2001, which is exactly 30 years.
Leap Years
In these 30 years, there are 7 leap years (1972, 1976, 1980, 1984, 1988, 1992, and 1996). This means there are 7 extra days in addition to the 30 years.
Total Days
So, the total number of days from 09/12/1971 to 09/12/2001 is 30 years (non-leap) + 7 days (leap) = 30 years + 7 days = 30 years + 1 week = 30 years + 7 days = 30 years + 1 day = 30 years + 1 day = 30 years + 7 days = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years +
To determine the day of the week for 09/12/1971, we need to calculate the number of days between 09/12/1971 and 09/12/2001, which is exactly 30 years.
Leap Years
In these 30 years, there are 7 leap years (1972, 1976, 1980, 1984, 1988, 1992, and 1996). This means there are 7 extra days in addition to the 30 years.
Total Days
So, the total number of days from 09/12/1971 to 09/12/2001 is 30 years (non-leap) + 7 days (leap) = 30 years + 7 days = 30 years + 1 week = 30 years + 7 days = 30 years + 1 day = 30 years + 1 day = 30 years + 7 days = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years + 1 day = 30 years +
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Community Answer
If 09/12/2001 happens to be Sunday, then 09/12/1971 would have been at...
09/12/2001—— Sunday
No. of days between 9/ 12/ 71 & 9 / 12/ 2001
we know every year has 1 odd days
we know leap year has 2 odd days
Here, No. of normal years = 22
And no. of leap years = 8
So odd days = 22 + 16 = 38 i.e 3 odd days (remainder when 38 is divided by 7, i.e. 3)
Hence, it was a Thursday.
No. of days between 9/ 12/ 71 & 9 / 12/ 2001
we know every year has 1 odd days
we know leap year has 2 odd days
Here, No. of normal years = 22
And no. of leap years = 8
So odd days = 22 + 16 = 38 i.e 3 odd days (remainder when 38 is divided by 7, i.e. 3)
Hence, it was a Thursday.
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