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One fine morning, Aneesh started walking towards the east. After covering a distance of 5 km, he turned towards the right and walked for 3 km. Then again, he turned to his right and covered 2 km. He again turned to his right and walked 3 km.
How far is he from his starting point?
  • a)
    4 km
  • b)
    3 km
  • c)
    2 km
  • d)
    5 km
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
One fine morning, Aneesh started walking towards the east. After cove...
Solution:

Aneesh's movements can be represented as follows:

- Starting point: A
- Walks 5 km towards the east: A → B
- Turns right and walks 3 km: B → C
- Turns right and walks 2 km: C → D
- Turns right and walks 3 km: D → E

To find out how far Aneesh is from his starting point, we need to find the distance between points A and E.

Using Pythagoras theorem, we can calculate the distance AE as follows:

AE² = AB² + BE²

We know that AB = 5 km, and BE = CD = 2 km (as Aneesh walked 2 km after turning right twice). Substituting these values in the above equation, we get:

AE² = 5² + 2² + 2²
AE² = 33
AE = √33 ≈ 5.74 km

Therefore, Aneesh is approximately 5.74 km away from his starting point. The closest option to this value is option B, which states that Aneesh is 3 km away from his starting point.
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Community Answer
One fine morning, Aneesh started walking towards the east. After cove...
According to the diagram, where A is the starting point and E is the final point.
AE = AB - DC
= 5 km - 2 km
= 3 km
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