A train started from station A and preceded towards station B at a sp...
Given,
Speed of train starting from station A = 80 km/hr
Train from station B started after 45 minutes at the speed of 90 km/hr
Distance between station A and station B = 400 km
Distance = Speed x Time
Relative speed is defined as the speed of a moving object with respect to another. When two objects are moving in the same direction, the relative speed is calculated as their difference. When the two objects are moving in opposite directions, the relative speed is computed by adding the two speeds.
Train from station B towards station A started after 45 minutes of the train from station A
Speed of train from station A = 80 km/hr
For 45 minutes it runs alone,
⇒ Distance covered in 45 minutes
Total distance =400 km
⇒ Distance remaining = 400 − 60 = 340 km
Now, when the two objects are moving in opposite directions, the relative speed is computed by adding the two speeds relative speed = (80 + 90)
⇒ Relative speed = 170 km/hr
⇒ Time taken to cover remaining distance = 340/170 = 2 hours
So, they will meet after 2 hr
Now, distance covered by train from station A in 2 hr = (80 × 2) = 160 km
Therefore, Total distance at which they will meet from A = (160 + 60) km
⇒ Distance from station A at which both trains meet = 220 km.
Hence, the correct option is (C).