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A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) is
- a)25, 130
- b)30,150
- c)20, 90
- d)10, 80
- e)None of these
Correct answer is option 'E'. Can you explain this answer?
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Most Upvoted Answer
A car after traveling 18 km from a point A developed some problem in ...
Let's assume that the original speed of the car is x km/hr.
Traveling from A to B
- Distance traveled from A to breakdown point = 18 km
- Distance traveled from breakdown point to B = total distance - distance traveled from A to breakdown point = (D-18) km
- Time taken to travel from A to breakdown point = 18/x hours
- Time taken to travel from breakdown point to B = (D-18)/(4x/5) hours (as the speed becomes 4/5 of the original speed)
- Total time taken = time taken from A to breakdown point + time taken from breakdown point to B + 45/60 hours (as it reached 45 minutes late)
So, the equation will be:
18/x + (D-18)/(4x/5) + 45/60 = (D/x) + 45/60
Simplifying the above equation, we get:
9x(D-18) = 20D(x+3)
Traveling from A to B (second scenario)
- Distance traveled from A to breakdown point = 30 km
- Distance traveled from breakdown point to B = total distance - distance traveled from A to breakdown point = (D-30) km
- Time taken to travel from A to breakdown point = 30/x hours
- Time taken to travel from breakdown point to B = (D-30)/(4x/5) hours (as the speed becomes 4/5 of the original speed)
- Total time taken = time taken from A to breakdown point + time taken from breakdown point to B + 36/60 hours (as it reached 36 minutes late)
So, the equation will be:
30/x + (D-30)/(4x/5) + 36/60 = (D/x) + 36/60
Simplifying the above equation, we get:
9x(D-30) = 16D(x+5)
Now, we have two equations:
9x(D-18) = 20D(x+3) --- Equation 1
9x(D-30) = 16D(x+5) --- Equation 2
Solving the above equations, we get:
D = 300 km and x = 60 km/hr
Therefore, the original speed of the car is 60 km/hr and the distance between points A and B is 300 km. None of the given options match this answer, so the correct answer is option E (None of these).
Traveling from A to B
- Distance traveled from A to breakdown point = 18 km
- Distance traveled from breakdown point to B = total distance - distance traveled from A to breakdown point = (D-18) km
- Time taken to travel from A to breakdown point = 18/x hours
- Time taken to travel from breakdown point to B = (D-18)/(4x/5) hours (as the speed becomes 4/5 of the original speed)
- Total time taken = time taken from A to breakdown point + time taken from breakdown point to B + 45/60 hours (as it reached 45 minutes late)
So, the equation will be:
18/x + (D-18)/(4x/5) + 45/60 = (D/x) + 45/60
Simplifying the above equation, we get:
9x(D-18) = 20D(x+3)
Traveling from A to B (second scenario)
- Distance traveled from A to breakdown point = 30 km
- Distance traveled from breakdown point to B = total distance - distance traveled from A to breakdown point = (D-30) km
- Time taken to travel from A to breakdown point = 30/x hours
- Time taken to travel from breakdown point to B = (D-30)/(4x/5) hours (as the speed becomes 4/5 of the original speed)
- Total time taken = time taken from A to breakdown point + time taken from breakdown point to B + 36/60 hours (as it reached 36 minutes late)
So, the equation will be:
30/x + (D-30)/(4x/5) + 36/60 = (D/x) + 36/60
Simplifying the above equation, we get:
9x(D-30) = 16D(x+5)
Now, we have two equations:
9x(D-18) = 20D(x+3) --- Equation 1
9x(D-30) = 16D(x+5) --- Equation 2
Solving the above equations, we get:
D = 300 km and x = 60 km/hr
Therefore, the original speed of the car is 60 km/hr and the distance between points A and B is 300 km. None of the given options match this answer, so the correct answer is option E (None of these).
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Community Answer
A car after traveling 18 km from a point A developed some problem in ...
At the original speed, and extra 12 kms (30-18) is covered in 9 minutes less.
This means, to reach 45 minutes less, car will have to travel 12 x 45/9 = 60 kms from a point 18 kms from Point A.
Total Distance from A to B = 18 + 60= 78 kms.
Hence, option 5.
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A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer?
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A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer?.
A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer?.
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A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer?, a detailed solution for A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer? has been provided alongside types of A car after traveling 18 km from a point A developed some problem in the engine and speed became 4/5 of its original speed. As a result, the car reached point B 45 minutes late. If the engine had developed the same problem after traveling 30 km from A, then it would have reached B only 36 minutes late. The original speed of the car (in km per hour) and the distance between the points A and B (in km.) isa)25, 130b)30,150c)20, 90d)10, 80e)None of theseCorrect answer is option 'E'. Can you explain this answer? theory, EduRev gives you an
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