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A and B together can complete the work in 30 days and the efficiency of A and B in the ratio of 7:5. If A started work and after 16 days left the work and the remaining work completed by B, then find in how many days the total work will be completed?
  • a)
    63.6 days
  • b)
    65.6 days
  • c)
    67.6 days
  • d)
    69.6 days
  • e)
    61.6 days
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A and B together can complete the work in 30 days and the efficiency ...
Let's assume that the total work is represented by the variable 'W'.

Given:
Efficiency of A and B is in the ratio of 7:5.
This means that if A completes 7 units of work in a given time, B completes 5 units of work in the same time.

Efficiency ratio of A and B = 7:5

Let the efficiency of A be 7x units of work per day.
And let the efficiency of B be 5x units of work per day.

According to the given information, A and B together can complete the work in 30 days.
So, the combined efficiency of A and B = (7x + 5x) = 12x units of work per day.

Therefore, the work done by A and B in 30 days = 30 * 12x = 360x units of work.

A started the work and after 16 days, A left the work.
So, the work done by A in 16 days = 16 * 7x = 112x units of work.

The remaining work that needs to be completed by B = Total work - Work done by A
Remaining work = 360x - 112x = 248x units of work.

Now, we need to find out how many days it will take for B to complete the remaining work.

Let the number of days it takes for B to complete the remaining work be 'd'.

The work done by B in 'd' days = d * 5x = 5dx units of work.

According to the given information, the work done by B in 'd' days is equal to the remaining work.
So, 5dx = 248x.

Simplifying the equation, we get:
5d = 248
d = 248/5
d = 49.6 days.

Therefore, it will take B 49.6 days to complete the remaining work.

Now, we need to find out the total number of days to complete the entire work.

Total number of days = Days worked by A + Days worked by B
Total number of days = 16 days + 49.6 days = 65.6 days.

Hence, the total work will be completed in 65.6 days.

Therefore, the correct answer is option B) 65.6 days.
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Community Answer
A and B together can complete the work in 30 days and the efficiency ...
A + B = 1/30
Time ratio of A and B = 5:7
1/5x + 1/7x = 1/30
12/35x = 1/30
x = 72/7
A alone complete the work = 72/7 * 5 = 360/7 days
B alone complete the work = 72/7 * 7 = 72 days
7 * 16/360 + y/72 = 1
y/72 = 31/45
y = 49.6
Total time = 16 + 49.6 = 65.6 days
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A and B together can complete the work in 30 days and the efficiency of A and B in the ratio of 7:5. If A started work and after 16 days left the work and the remaining work completed by B, then find in how many days the total work will be completed?a)63.6 daysb)65.6 daysc)67.6 daysd)69.6 dayse)61.6 daysCorrect answer is option 'B'. Can you explain this answer?
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