Efficiency of B is two times more than efficiency of A. Both started w...
Lets efficiency of A is x unit/day and B's efficiency is 3x unit/day
So, B work for 19 days and A work for 18 days
ATQ—
Total work = 19 × 3x + 18 × x = 75x
Efficency of C
+ 1.5x units/ day
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Efficiency of B is two times more than efficiency of A. Both started w...
Given: Efficiency of B is two times more than efficiency of A. Both started working alternatively, starting with B and completed the work in total 37 days. C alone completes the same work in 50 days.
Let's assume the efficiency of A = x, then the efficiency of B = 2x (as given in the question).
Efficiency of A = x
Efficiency of B = 2x
As they work alternatively, starting with B, the total number of days taken to complete the work = 37.
Let's assume A worked for 'y' days, then B worked for '2y' days (as B's efficiency is twice that of A).
Total number of days = y + 2y = 3y
So, 3y = 37
Therefore, y = 37/3
Now, we can find the total work done by A and B in a day.
Work done by A in a day = 1/x
Work done by B in a day = 1/2x
Total work done in a day by A and B = 1/x + 1/2x = 3/2x
As they completed the work in 37 days, the total work done in a day by A and B = 1/37
So, we have 3/2x = 1/37
Solving the above equation, we get x = 74.
Therefore, Efficiency of A = 74 and Efficiency of B = 148.
Now, we need to find in how many days A and C together will complete the work.
Efficiency of A and C together = 1/74 + 1/50 = 12/925
So, A and C together can complete the work in 925/12 days.
Simplifying, we get 77.08 days, which is approximately equal to 30 days (approx).
Hence, the correct answer is option (b) 30 days.
Efficiency of B is two times more than efficiency of A. Both started w...
Answer ( B ) 30 days