If p:q is the sub-duplicate ratio of p-x2:q-x2 then x2 is?
**Understanding the Question:**
The question states that p:q is the sub-duplicate ratio of p-x^2 : q-x^2. We need to find the value of x^2.
**Sub-Duplicate Ratio:**
The sub-duplicate ratio of two quantities a and b is the ratio of the square root of a to the square root of b. Mathematically, it can be expressed as:
Sub-duplicate ratio = √a / √b
**Formulation of the Problem:**
According to the given question, p:q is the sub-duplicate ratio of p-x^2 : q-x^2. Let's formulate this statement mathematically:
√(p-x^2) / √(q-x^2) = p / q
**Squaring Both Sides:**
To solve the equation, let's square both sides:
[√(p-x^2) / √(q-x^2)]^2 = (p / q)^2
(p-x^2) / (q-x^2) = p^2 / q^2
**Cross-Multiplication:**
Next, let's cross-multiply the equation:
p^2(q-x^2) = q^2(p-x^2)
p^2q - p^2x^2 = q^2p - q^2x^2
**Rearranging the Equation:**
Rearranging the equation, we get:
p^2q - q^2p = p^2x^2 - q^2x^2
pq(p - q) = x^2(p^2 - q^2)
**Simplifying the Equation:**
Further simplifying the equation, we have:
pq(p - q) = x^2(p - q)(p + q)
**Dividing Both Sides:**
Now, let's divide both sides of the equation by (p - q):
pq = x^2(p + q)
**Simplifying Further:**
Finally, we can express x^2 in terms of p and q:
x^2 = (pq) / (p + q)
Therefore, x^2 is equal to the ratio of the product of p and q to the sum of p and q.
**Conclusion:**
In conclusion, x^2 is equal to (pq) / (p + q) based on the given sub-duplicate ratio.