Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > An air-core radio-frequency transformer as sh...
Start Learning for Free
An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.
(Round off to 2 decimal places.)
(Round off to 2 decimal places.)
Correct answer is between '50,52'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
An air-core radio-frequency transformer as shown has a primary winding...
Concept:
Mutual Inductance:
When two coils are placed close to each other, a change in current in the first coil produces a change in magnetic flux, which cuts not only the coil itself but also the second coil as well. The change in the flux induces a voltage in the second coil, this voltage is called induced voltage and the two coils are said to have a mutual inductance.
Consider a pair of coupled inductors with self-inductance L1 and L2, magnetically coupled through coupling coefficient k.
Input and output voltage expressions are given as
V1 = jωL1I1 + jωMI2 ...(1)
V2 = jωL2I2 + jωMI1 ...(2)
Where,
ω = 2πf
M = Mutual inductance
L1 = Inductance of coil one
L2 = Inductance of coil two
Calculation:
In the given circuit secondary is open-circuited, so I2 = 0 A
Given secondary voltage V2 = 7.3 Vp-p
The output voltage expression from equation(2) is given as
V2 = jωMI1 ....(3)
The given voltage across the 22 Ω resistor is 5 Vp-p
So primary current is calculated as I1 = 5 / 22 Ap-p
From equation(3)
|V2| = 2π f M I1
7.3 = 2 × π × 100 × 103 × M × (5/22)
M = 51.12 μH
Mutual Inductance:
When two coils are placed close to each other, a change in current in the first coil produces a change in magnetic flux, which cuts not only the coil itself but also the second coil as well. The change in the flux induces a voltage in the second coil, this voltage is called induced voltage and the two coils are said to have a mutual inductance.
Consider a pair of coupled inductors with self-inductance L1 and L2, magnetically coupled through coupling coefficient k.
Input and output voltage expressions are given as
V1 = jωL1I1 + jωMI2 ...(1)
V2 = jωL2I2 + jωMI1 ...(2)
Where,
ω = 2πf
M = Mutual inductance
L1 = Inductance of coil one
L2 = Inductance of coil two
Calculation:
In the given circuit secondary is open-circuited, so I2 = 0 A
Given secondary voltage V2 = 7.3 Vp-p
The output voltage expression from equation(2) is given as
V2 = jωMI1 ....(3)
The given voltage across the 22 Ω resistor is 5 Vp-p
So primary current is calculated as I1 = 5 / 22 Ap-p
From equation(3)
|V2| = 2π f M I1
7.3 = 2 × π × 100 × 103 × M × (5/22)
M = 51.12 μH
Free Test
FREE
| Start Free Test |
Community Answer
An air-core radio-frequency transformer as shown has a primary winding...
Concept:
Mutual Inductance:
When two coils are placed close to each other, a change in current in the first coil produces a change in magnetic flux, which cuts not only the coil itself but also the second coil as well. The change in the flux induces a voltage in the second coil, this voltage is called induced voltage and the two coils are said to have a mutual inductance.
Consider a pair of coupled inductors with self-inductance L1 and L2, magnetically coupled through coupling coefficient k.
Input and output voltage expressions are given as
V1 = jωL1I1 + jωMI2 ...(1)
V2 = jωL2I2 + jωMI1 ...(2)
Where,
ω = 2πf
M = Mutual inductance
L1 = Inductance of coil one
L2 = Inductance of coil two
Calculation:
In the given circuit secondary is open-circuited, so I2 = 0 A
Given secondary voltage V2 = 7.3 Vp-p
The output voltage expression from equation(2) is given as
V2 = jωMI1 ....(3)
The given voltage across the 22 Ω resistor is 5 Vp-p
So primary current is calculated as I1 = 5 / 22 Ap-p
From equation(3)
|V2| = 2π f M I1
7.3 = 2 × π × 100 × 103 × M × (5/22)
M = 51.12 μH
Mutual Inductance:
When two coils are placed close to each other, a change in current in the first coil produces a change in magnetic flux, which cuts not only the coil itself but also the second coil as well. The change in the flux induces a voltage in the second coil, this voltage is called induced voltage and the two coils are said to have a mutual inductance.
Consider a pair of coupled inductors with self-inductance L1 and L2, magnetically coupled through coupling coefficient k.
Input and output voltage expressions are given as
V1 = jωL1I1 + jωMI2 ...(1)
V2 = jωL2I2 + jωMI1 ...(2)
Where,
ω = 2πf
M = Mutual inductance
L1 = Inductance of coil one
L2 = Inductance of coil two
Calculation:
In the given circuit secondary is open-circuited, so I2 = 0 A
Given secondary voltage V2 = 7.3 Vp-p
The output voltage expression from equation(2) is given as
V2 = jωMI1 ....(3)
The given voltage across the 22 Ω resistor is 5 Vp-p
So primary current is calculated as I1 = 5 / 22 Ap-p
From equation(3)
|V2| = 2π f M I1
7.3 = 2 × π × 100 × 103 × M × (5/22)
M = 51.12 μH
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer?
Question Description
An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer?.
An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer?.
Solutions for An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer?, a detailed solution for An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? has been provided alongside types of An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An air-core radio-frequency transformer as shown has a primary winding and a secondary winding. The mutual inductance M between the windings of the transformer is ______ μH.(Round off to 2 decimal places.)Correct answer is between '50,52'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup