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A single phase transformer has 400 primary and 800 secondary turns. The net cross-sectional area of the core is 40 cm. If the primary winding be connected to a 50 Hz supply at 500 Volts calculate :

1. The peak value of the flux density in the core.

2. The voltage Induced in the secondary.?
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A single phase transformer has 400 primary and 800 secondary turns. Th...
Calculation of Peak Value of Flux Density in the Core

  • The formula for calculating the peak value of flux density in a transformer core is Bmax = (Vp * 10^8) / (4.44 * Np * Ac * f)

  • Where Bmax is the peak value of flux density, Vp is the primary voltage, Np is the number of turns in the primary winding, Ac is the net cross-sectional area of the core, and f is the frequency of the supply.

  • Substituting the given values, we get Bmax = (500 * 10^8) / (4.44 * 400 * 40 * 50) = 0.283 tesla.



Calculation of Voltage Induced in the Secondary

  • The formula for calculating the voltage induced in the secondary winding is Vs = (Np / Ns) * Vp

  • Where Vs is the voltage induced in the secondary winding, Ns is the number of turns in the secondary winding, and Vp is the primary voltage.

  • Substituting the given values, we get Vs = (400 / 800) * 500 = 250 volts.



Explanation

  • The peak value of flux density in a transformer core is directly proportional to the primary voltage and the frequency of the supply, and inversely proportional to the number of turns in the primary winding and the net cross-sectional area of the core.

  • The voltage induced in the secondary winding is directly proportional to the primary voltage and the ratio of the number of turns in the primary and secondary windings.

  • The given problem can be solved using the above formulas by substituting the given values and calculating the required quantities.

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A single phase transformer has 400 primary and 800 secondary turns. The net cross-sectional area of the core is 40 cm. If the primary winding be connected to a 50 Hz supply at 500 Volts calculate :1. The peak value of the flux density in the core.2. The voltage Induced in the secondary.?
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A single phase transformer has 400 primary and 800 secondary turns. The net cross-sectional area of the core is 40 cm. If the primary winding be connected to a 50 Hz supply at 500 Volts calculate :1. The peak value of the flux density in the core.2. The voltage Induced in the secondary.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A single phase transformer has 400 primary and 800 secondary turns. The net cross-sectional area of the core is 40 cm. If the primary winding be connected to a 50 Hz supply at 500 Volts calculate :1. The peak value of the flux density in the core.2. The voltage Induced in the secondary.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single phase transformer has 400 primary and 800 secondary turns. The net cross-sectional area of the core is 40 cm. If the primary winding be connected to a 50 Hz supply at 500 Volts calculate :1. The peak value of the flux density in the core.2. The voltage Induced in the secondary.?.
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