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Two identical coils X and Y of 500 turns each lie in parallel planes such that 80% of flux produced by one coil links with the other. If a current of 5 A flowing in X produces a flux of 10 mWb in it, find the mutual inductance between X and Y
- a)0.8 H
- b)8 H
- c)0.16 H
- d)16 H
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
Two identical coils X and Y of 500 turns each lie in parallel planes s...
Given:
Number of turns in coil X and Y, N = 500
Mutual flux linkage between X and Y, λ = 0.8Φ
Current flowing through X, I = 5 A
Flux produced by X, Φ = 10 mWb
To find: Mutual inductance between X and Y, M
Formula used: Mutual inductance, M = λ/I
Calculation:
Mutual flux linkage between X and Y, λ = 0.8Φ = 0.8 × 10 mWb = 8 mWb
Current flowing through X, I = 5 A
Mutual inductance between X and Y, M = λ/I = (8 mWb)/(5 A) = 1.6 H
Therefore, the correct answer is option A, i.e., 0.8 H.
HTML Format:
Given:
To find: Mutual inductance between X and Y, M
Formula used: Mutual inductance, M = λ/I
Calculation:
Therefore, the correct answer is option A, i.e., 0.8 H.
Number of turns in coil X and Y, N = 500
Mutual flux linkage between X and Y, λ = 0.8Φ
Current flowing through X, I = 5 A
Flux produced by X, Φ = 10 mWb
To find: Mutual inductance between X and Y, M
Formula used: Mutual inductance, M = λ/I
Calculation:
Mutual flux linkage between X and Y, λ = 0.8Φ = 0.8 × 10 mWb = 8 mWb
Current flowing through X, I = 5 A
Mutual inductance between X and Y, M = λ/I = (8 mWb)/(5 A) = 1.6 H
Therefore, the correct answer is option A, i.e., 0.8 H.
HTML Format:
Given:
- Number of turns in coil X and Y, N = 500
- Mutual flux linkage between X and Y, λ = 0.8Φ
- Current flowing through X, I = 5 A
- Flux produced by X, Φ = 10 mWb
To find: Mutual inductance between X and Y, M
Formula used: Mutual inductance, M = λ/I
Calculation:
- Mutual flux linkage between X and Y, λ = 0.8Φ = 0.8 × 10 mWb = 8 mWb
- Current flowing through X, I = 5 A
- Mutual inductance between X and Y, M = λ/I = (8 mWb)/(5 A) = 1.6 H
Therefore, the correct answer is option A, i.e., 0.8 H.
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Community Answer
Two identical coils X and Y of 500 turns each lie in parallel planes s...
Concept:
Consider two coils having self-inductance L1 and L2 placed very close to each other. Let the number of turns of the two coils be N1 and N2 respectively. Let coil A carries current I1 and coil B carries current I2.
Due to current I1, the flux produced is ϕ1 which links with both the coils. Then the mutual inductance between two coils can be written as
Here, ϕ12 is the part of the flux ϕ1 linking with the coil 2
Calculation:
Number of turns = N1 = N2 = 500
Current (I) = 5 A
Flux produced in coil X (ϕ1) = 10 mwb
Flux linked with Y (ϕ12) = 80% of flux produced in coil 1 = 8 mwb
Mutual inductance
Consider two coils having self-inductance L1 and L2 placed very close to each other. Let the number of turns of the two coils be N1 and N2 respectively. Let coil A carries current I1 and coil B carries current I2.
Due to current I1, the flux produced is ϕ1 which links with both the coils. Then the mutual inductance between two coils can be written as
Here, ϕ12 is the part of the flux ϕ1 linking with the coil 2
Calculation:
Number of turns = N1 = N2 = 500
Current (I) = 5 A
Flux produced in coil X (ϕ1) = 10 mwb
Flux linked with Y (ϕ12) = 80% of flux produced in coil 1 = 8 mwb
Mutual inductance
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Two identical coils X and Y of 500 turns each lie in parallel planes such that 80% of flux produced by one coil links with the other. If a current of 5 A flowing in X produces a flux of 10 mWb in it, find the mutual inductance between X and Ya)0.8 Hb)8 Hc)0.16 Hd)16 HCorrect answer is option 'A'. Can you explain this answer?
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