The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearlya)5.4 mHb)162 mHc)0.006 mHd)0.0002 mHCorrect answer is option 'B'. Can you explain this answer? - EduRev Electrical Engineering (EE) Question

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The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearly

a)
5.4 mH
b)
162 mH
c)
0.006 mH
d)
0.0002 mH

Correct answer is option 'B'. Can you explain this answer?

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The coefficient of self-inductance of a solenoid is 0.18 mH. If a core...

Concept:

Self-Induction:

Whenever the electric current passing through a coil changes, the magnetic flux linked with it will also change.
- As a result of this, in accordance with Faraday’s laws of electromagnetic induction, an emf is induced in the coil which opposes the change that causes it.
- This phenomenon is called ‘self-induction’ and the emf induced is called back emf, current so produced in the coil is called induced current.
- The self-inductance of a solenoid is given by:

Where N = number of turns, A = area of cross-section, l = length of the solenoid and μ₀ = absolute permeability

Calculation:
Give - L₁ = 0.18 mH = 0.18 x 10^-3 H , μ₁ = μ_₀μ, μ₂ = μ_₀ and relative permeability (μ) = 900

The self-inductance of a solenoid is given by:

Here N, A and l is constant
∴ L ∝ μ

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The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearlya)5.4 mHb)162 mHc)0.006 mHd)0.0002 mHCorrect answer is option 'B'. Can you explain this answer?

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The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearlya)5.4 mHb)162 mHc)0.006 mHd)0.0002 mHCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearlya)5.4 mHb)162 mHc)0.006 mHd)0.0002 mHCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The coefficient of self-inductance of a solenoid is 0.18 mH. If a core of soft iron of relative permeability 900 is inserted, then the coefficient of self-inductance will become nearlya)5.4 mHb)162 mHc)0.006 mHd)0.0002 mHCorrect answer is option 'B'. Can you explain this answer?.

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