Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A 4 pole 220V shunt motor has 540 lap wound c...
Start Learning for Free
A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution?
Most Upvoted Answer
A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A fr...
Problem: A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed.
Solution:
Given:
- Number of poles (P) = 4
- Supply voltage (V) = 220V
- Armature current (Ia) = 32A
- Field current (If) = 1A
- Output power (Pout) = 5.5 kW
- Armature resistance (Ra) = 0.09 Ω
- Flux per pole (Φ) = 30 mWb
- Number of conductors (N) = 540
Formula:
- Speed (N) = (120 * f) / P
- Torque (T) = (Pout * 1000) / N
- Back EMF (Eb) = (Φ * P * N) / (60 * 10^3)
- Armature voltage (Va) = V - (Ia * Ra)
- Total current (I) = Ia + If
- Power input (Pin) = V * I
- Efficiency (η) = Pout / Pin
Calculation:
- Calculating frequency (f) from supply voltage (V) = 220V
- f = 50 Hz
- Calculating speed (N)
- N = (120 * f) / P
- N = (120 * 50) / 4
- N = 1500 rpm
- Calculating back EMF (Eb)
- Eb = (Φ * P * N) / (60 * 10^3)
- Eb = (30 * 10^-3 * 4 * 1500) / (60 * 10^3)
- Eb = 0.3 V
- Calculating armature voltage (Va)
- Va = V - (Ia * Ra)
- Va = 220 - (32 * 0.09)
- Va = 217.72 V
- Calculating total current (I)
- I = Ia + If
- I = 32 + 1
- I = 33 A
- Calculating power input (Pin)
- Pin = V * I
- Pin = 220 * 33
- Pin = 7260 W
- Calculating efficiency (η)
- η = Pout / Pin
- η = (5.5 * 10^3) / 7260
- η = 0.758
- Calculating torque (T)
- T = (Pout * 1000) / N
- T = (5.5 * 10^3) / 1500
- T = 3.67 Nm
Answer:
- Speed (N) = 1500 rpm
- Torque (T) = 3.67 N
Solution:
Given:
- Number of poles (P) = 4
- Supply voltage (V) = 220V
- Armature current (Ia) = 32A
- Field current (If) = 1A
- Output power (Pout) = 5.5 kW
- Armature resistance (Ra) = 0.09 Ω
- Flux per pole (Φ) = 30 mWb
- Number of conductors (N) = 540
Formula:
- Speed (N) = (120 * f) / P
- Torque (T) = (Pout * 1000) / N
- Back EMF (Eb) = (Φ * P * N) / (60 * 10^3)
- Armature voltage (Va) = V - (Ia * Ra)
- Total current (I) = Ia + If
- Power input (Pin) = V * I
- Efficiency (η) = Pout / Pin
Calculation:
- Calculating frequency (f) from supply voltage (V) = 220V
- f = 50 Hz
- Calculating speed (N)
- N = (120 * f) / P
- N = (120 * 50) / 4
- N = 1500 rpm
- Calculating back EMF (Eb)
- Eb = (Φ * P * N) / (60 * 10^3)
- Eb = (30 * 10^-3 * 4 * 1500) / (60 * 10^3)
- Eb = 0.3 V
- Calculating armature voltage (Va)
- Va = V - (Ia * Ra)
- Va = 220 - (32 * 0.09)
- Va = 217.72 V
- Calculating total current (I)
- I = Ia + If
- I = 32 + 1
- I = 33 A
- Calculating power input (Pin)
- Pin = V * I
- Pin = 220 * 33
- Pin = 7260 W
- Calculating efficiency (η)
- η = Pout / Pin
- η = (5.5 * 10^3) / 7260
- η = 0.758
- Calculating torque (T)
- T = (Pout * 1000) / N
- T = (5.5 * 10^3) / 1500
- T = 3.67 Nm
Answer:
- Speed (N) = 1500 rpm
- Torque (T) = 3.67 N
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution?
Question Description
A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution?.
A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution?.
Solutions for A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? defined & explained in the simplest way possible. Besides giving the explanation of
A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution?, a detailed solution for A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? has been provided alongside types of A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? theory, EduRev gives you an
ample number of questions to practice A 4 pole 220V shunt motor has 540 lap wound conductor. It takes 32A from the supply main and develops output power of 5.5rW. The field winding takes 1A. Armature resistance is 0.09Ω and flux per pole is 30mWb. Find: a. speed. b. Torque developed What will be the solution? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup