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A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.
Correct answer is '14.14'. Can you explain this answer?
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A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux...
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A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux...
The Correct answer is 57.86 N-m.
Trust me guys your answer is absolutely wrong, Please do the needful...
Trust me guys your answer is absolutely wrong, Please do the needful...
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A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux...
The given specifications for the DC motor are as follows:
- Power (P): 10 hp
- Current (I): 37.5 A
- Voltage (V): 230V
Additionally, the motor has the following characteristics:
- Flux per pole (ϕ/pole): 0.01 Wb
- Number of poles (p): 4
- Number of conductors (Nc): 666
- Number of parallel paths (Z): 2
- Armature resistance (Ra): 0.267 Ω
Let's calculate some additional parameters based on the given information.
1. Power in Watts (Pw):
We need to convert the given power from horsepower (hp) to watts (W).
1 hp = 746 W
Pw = 10 hp * 746 W/hp = 7460 W
2. Torque (T):
The torque can be calculated using the formula:
T = (Pw * 60) / (2 * π * N)
Where N is the speed in RPM.
Since the RPM is not given, we cannot calculate the torque without this information.
3. Back EMF (Eb):
The back EMF can be calculated using the formula:
Eb = V - (I * Ra)
Where V is the voltage and I is the current.
Eb = 230V - (37.5 A * 0.267 Ω) = 230V - 10.0125 V = 219.9875 V
4. Speed (N):
The speed can be calculated using the formula:
Eb = (ϕ * N * Z) / (60 * p)
Where ϕ is the flux per pole, N is the speed in RPM, Z is the number of parallel paths, and p is the number of poles.
Rearranging the formula, we get:
N = (Eb * 60 * p) / (ϕ * Z)
N = (219.9875V * 60 * 4) / (0.01 Wb * 2)
N = 131992.5 RPM
Please note that the torque and speed calculations require the speed in RPM, which was not provided in the given specifications. If you have the RPM value, you can substitute it into the torque and speed formulas to calculate those parameters as well.
- Power (P): 10 hp
- Current (I): 37.5 A
- Voltage (V): 230V
Additionally, the motor has the following characteristics:
- Flux per pole (ϕ/pole): 0.01 Wb
- Number of poles (p): 4
- Number of conductors (Nc): 666
- Number of parallel paths (Z): 2
- Armature resistance (Ra): 0.267 Ω
Let's calculate some additional parameters based on the given information.
1. Power in Watts (Pw):
We need to convert the given power from horsepower (hp) to watts (W).
1 hp = 746 W
Pw = 10 hp * 746 W/hp = 7460 W
2. Torque (T):
The torque can be calculated using the formula:
T = (Pw * 60) / (2 * π * N)
Where N is the speed in RPM.
Since the RPM is not given, we cannot calculate the torque without this information.
3. Back EMF (Eb):
The back EMF can be calculated using the formula:
Eb = V - (I * Ra)
Where V is the voltage and I is the current.
Eb = 230V - (37.5 A * 0.267 Ω) = 230V - 10.0125 V = 219.9875 V
4. Speed (N):
The speed can be calculated using the formula:
Eb = (ϕ * N * Z) / (60 * p)
Where ϕ is the flux per pole, N is the speed in RPM, Z is the number of parallel paths, and p is the number of poles.
Rearranging the formula, we get:
N = (Eb * 60 * p) / (ϕ * Z)
N = (219.9875V * 60 * 4) / (0.01 Wb * 2)
N = 131992.5 RPM
Please note that the torque and speed calculations require the speed in RPM, which was not provided in the given specifications. If you have the RPM value, you can substitute it into the torque and speed formulas to calculate those parameters as well.
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A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer?
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A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer?.
A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer?.
Solutions for A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
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A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer?, a detailed solution for A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer? has been provided alongside types of A DC motor has the following specifications: 10 hp, 37.5 A, 230V; flux/pole = 0.01 Wb, number of poles = 4, number of conductors = 666, number of parallel paths = 2. Armature resistance = 0.267Ω. The armature reaction is negligible and rotational losses are 600W. The motor operates from a 230V DC supply. If the motor runs at 1000 rpm, the output torque produced in (in Nm) is __________.Correct answer is '14.14'. Can you explain this answer? theory, EduRev gives you an
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