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An FM signal is given as;
Where m(t) is shown in the figure given below.
It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal.
Where m(t) is shown in the figure given below.
It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal.
- a)fi =998.407 MHz , δf = 5000\π Hz
- b)fi =99.8407 kHz , δf = 5\π kHz
- c)fi = 0.998407 MHz , δf = 5\π kHz
- d)fi = 998.407 kHz , δf = 50\π kHz
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
An FM signal is given as;Where m(t) is shown in the figure given below...
Concept:
Standard expression of FM signal
Instantaneous frequency (fi in Hz)
Where
From the standard expression
Peak frequency deviation:
Standard expression of FM signal
Instantaneous frequency (fi in Hz)
Where
From the standard expression
Peak frequency deviation:
Calculation:
Given;
at, t = 1.5 sec ; m(t) = -10
Given;
at, t = 1.5 sec ; m(t) = -10
Peak frequency deviation:
|m(t)|max = 10
|m(t)|max = 10
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Community Answer
An FM signal is given as;Where m(t) is shown in the figure given below...
Concept:
Standard expression of FM signal
Instantaneous frequency (fi in Hz)
Where
From the standard expression
Peak frequency deviation:
Standard expression of FM signal
Instantaneous frequency (fi in Hz)
Where
From the standard expression
Peak frequency deviation:
Calculation:
Given;
at, t = 1.5 sec ; m(t) = -10
Given;
at, t = 1.5 sec ; m(t) = -10
Peak frequency deviation:
|m(t)|max = 10
|m(t)|max = 10
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An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer?
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An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer?.
An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer?.
Solutions for An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE).
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Here you can find the meaning of An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice An FM signal is given as;Where m(t) is shown in the figure given below.It is given that carrier frequency (fc) is 1000kHz. Then calculate the value of instantaneous frequency (fi) at t = 1.5 sec and the peak frequency deviation (δf) of the above FM signal. a)fi =998.407 MHz , δf = 5000\π Hzb)fi =99.8407 kHz , δf = 5\π kHzc)fi = 0.998407 MHz , δf = 5\π kHzd)fi = 998.407 kHz , δf = 50\π kHzCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.
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