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Which of the following statement is true for a wavelength of 1000 nm. A p-n photodiode is fabricated from a semiconductor with band gap of 1.9 eV.
- a)The photodiode can detect signal once the energy of signal is increased
- b)The energy of a signal of given wavelength is more than the specified band gap
- c)The photodiode can easily detect signal
- d)The photodiode cannot detect signal
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Which of the following statement is true for a wavelength of 1000 nm. ...
**Answer:**
**Explanation:**
The correct answer is option 'D' - The photodiode cannot detect the signal.
To understand why this is the correct answer, we need to consider the concept of band gap and its relation to the detection of signals by a photodiode.
**Band Gap:**
The band gap is the energy difference between the valence band (VB) and the conduction band (CB) in a semiconductor material. It represents the energy required to move an electron from the valence band to the conduction band.
In the given question, the band gap of the semiconductor material used to fabricate the photodiode is specified as 1.9 eV.
**Wavelength and Energy:**
The energy of a signal is inversely proportional to its wavelength. The relationship between energy (E) and wavelength (λ) can be described by the equation:
E = hc/λ
where h is Planck's constant and c is the speed of light.
In the question, the wavelength of the signal is given as 1000 nm. To calculate the energy of the signal, we can use the equation:
E = hc/λ = (6.626 x 10^-34 J.s) x (3 x 10^8 m/s) / (1000 x 10^-9 m)
Simplifying the equation, we find:
E = 6.626 x 10^-19 J
Converting the energy from joules to electron volts (eV), we divide by the elementary charge (1.602 x 10^-19 C):
E = (6.626 x 10^-19 J) / (1.602 x 10^-19 C/eV) = 4.14 eV
**Comparison with Band Gap:**
The energy of the signal (4.14 eV) is greater than the band gap of the semiconductor material (1.9 eV). In order for a photodiode to detect a signal, the energy of the signal must be equal to or greater than the band gap of the semiconductor material. This allows the signal to excite electrons from the valence band to the conduction band, creating a photocurrent.
In this case, the energy of the signal (4.14 eV) is greater than the band gap (1.9 eV), so the photodiode cannot detect the signal. The energy of the signal is not sufficient to generate a photocurrent in the photodiode.
Therefore, the correct answer is option 'D' - The photodiode cannot detect the signal.
**Explanation:**
The correct answer is option 'D' - The photodiode cannot detect the signal.
To understand why this is the correct answer, we need to consider the concept of band gap and its relation to the detection of signals by a photodiode.
**Band Gap:**
The band gap is the energy difference between the valence band (VB) and the conduction band (CB) in a semiconductor material. It represents the energy required to move an electron from the valence band to the conduction band.
In the given question, the band gap of the semiconductor material used to fabricate the photodiode is specified as 1.9 eV.
**Wavelength and Energy:**
The energy of a signal is inversely proportional to its wavelength. The relationship between energy (E) and wavelength (λ) can be described by the equation:
E = hc/λ
where h is Planck's constant and c is the speed of light.
In the question, the wavelength of the signal is given as 1000 nm. To calculate the energy of the signal, we can use the equation:
E = hc/λ = (6.626 x 10^-34 J.s) x (3 x 10^8 m/s) / (1000 x 10^-9 m)
Simplifying the equation, we find:
E = 6.626 x 10^-19 J
Converting the energy from joules to electron volts (eV), we divide by the elementary charge (1.602 x 10^-19 C):
E = (6.626 x 10^-19 J) / (1.602 x 10^-19 C/eV) = 4.14 eV
**Comparison with Band Gap:**
The energy of the signal (4.14 eV) is greater than the band gap of the semiconductor material (1.9 eV). In order for a photodiode to detect a signal, the energy of the signal must be equal to or greater than the band gap of the semiconductor material. This allows the signal to excite electrons from the valence band to the conduction band, creating a photocurrent.
In this case, the energy of the signal (4.14 eV) is greater than the band gap (1.9 eV), so the photodiode cannot detect the signal. The energy of the signal is not sufficient to generate a photocurrent in the photodiode.
Therefore, the correct answer is option 'D' - The photodiode cannot detect the signal.
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Community Answer
Which of the following statement is true for a wavelength of 1000 nm. ...
Concept
A p-n photodiode can only detect those signals whose excitation energy is greater than the band gap energy of the p-n photodiode.
Energy associated with a wave is calculated by the formula
where,
h = plank's constant
c = velocity of the wave i.e. light
λ = wavelength of the signal
A p-n photodiode can only detect those signals whose excitation energy is greater than the band gap energy of the p-n photodiode.
Energy associated with a wave is calculated by the formula
where,
h = plank's constant
c = velocity of the wave i.e. light
λ = wavelength of the signal
Calculation
Given λ = 1000nm = 10-6m
h = 6.6 x10-34 m2kg/s
c = 3x108 m/s
Now we know that 1eV = 1.6 x 10-19J
Since the energy of the signal is 1.23eV less than the energy band gap (1.9eV) of the semiconductor, Hence the signal cannot be detected by the p-n photodiode.
Given λ = 1000nm = 10-6m
h = 6.6 x10-34 m2kg/s
c = 3x108 m/s
Now we know that 1eV = 1.6 x 10-19J
Since the energy of the signal is 1.23eV less than the energy band gap (1.9eV) of the semiconductor, Hence the signal cannot be detected by the p-n photodiode.
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Which of the following statement is true for a wavelength of 1000 nm. A p-n photodiode is fabricated from a semiconductor with band gap of 1.9 eV.a)The photodiode can detect signal once the energy of signal is increasedb)The energy of a signal of given wavelength is more than the specified band gapc)The photodiode can easily detect signald)The photodiode cannot detect signalCorrect answer is option 'D'. Can you explain this answer?
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