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If x=m is one of the solutions of the equation 2x^2 5x-m=0 the possible value of m are?
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If x=m is one of the solutions of the equation 2x^2 5x-m=0 the possibl...
Solution:

The given equation is 2x^2 +5x -m = 0.

Substituting x=m in the above equation, we get

2m^2 + 5m - m = 0

2m^2 + 4m = 0

2m(m+2) = 0

Therefore, m = 0 or m = -2.

Hence, the possible values of m are 0 and -2.

Explanation:

To solve the problem, we need to substitute x = m in the given equation and simplify it. This will give us an equation in terms of m. To find the possible values of m, we need to solve this equation.

Here, we get an equation in terms of m as 2m^2 + 5m - m = 0. Simplifying this equation, we get 2m^2 + 4m = 0. Factoring out 2m from the left-hand side, we get 2m(m+2) = 0. Using the zero product property, we get m = 0 or m = -2.

Therefore, the possible values of m are 0 and -2.
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If x=m is one of the solutions of the equation 2x^2 5x-m=0 the possible value of m are?
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