Directions: Read the information carefully and answer the question.Th...
The Venn diagram for the given problem is as given in figure 1.
Firstly, there are 28 candidates placed in all the 3 companies.
So, 28 goes into the common region.
Then, 60 candidates were selected by both L and M.
So, 60 - 28 = 32 goes into the region common only to L and M.
Now, number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M.
Thus, number of candidates selected by both M and N = 2 × 60 - 68 = 120 - 68 = 52
Thus, 52 - 28 = 24 goes into the region common to both M and N.
Now, number of candidates selected by both L and N = 2 × 28 = 56
Thus, 56 - 28 = 28 goes into the region common to both L and N.
Now, let the total number of candidates selected = T
Number of candidates selected by both L and N = 56
So, 56 = T(1 - 0.9188) or T = 690
As equal number of candidates were selected by the 3 companies, the number of candidates in each company = 690/3 = 230
Thus, 230 - (32 + 28 + 28) = 230 - 88 = 142 goes into the region exclusive to L.
230 - (28 + 28 + 24) = 230 - 80 = 150 goes into the region exclusive to N.
230 - (32 + 28 + 24) = 230 - 84 = 146 goes into the region exclusive to M.
From the Venn diagram, it is clear that number of candidates selected by only L or M = Number of candidates selected by L or M and not by N = 142 + 32 + 146 = 320
Hence, answer option (c) is correct.