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Directions: Read the information carefully and answer the question.
Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.
Q. Find the total number of candidates who were selected only by company L or M.
  • a)
    240
  • b)
    260
  • c)
    320
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Directions: Read the information carefully and answer the question.Th...
Given Information:
- Three companies L, M, and N participated in campus recruitment in college Z.
- All three companies selected an equal number of candidates.
- 60 candidates were selected by both L and M.
- The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M.
- 28 candidates got placed in all three companies.
- This number (28) was 50% less than the number of candidates selected by both L and N.
- The total number of candidates selected by both L and N was 91.88% less than the total number of candidates selected by all three companies.

Let's solve the problem step by step:

Step 1: Find the number of candidates selected by both M and N.
Let's assume the number of candidates selected by both L and M is x.
The number of candidates selected by both M and N is twice the number of candidates selected by both L and M minus 68.
So, the number of candidates selected by both M and N = 2x - 68.

Step 2: Find the number of candidates selected by both L and N.
The number of candidates placed in all three companies is 28.
According to the given condition, this number is 50% less than the number of candidates selected by both L and N.
So, 28 = (50/100) * (Number of candidates selected by both L and N).

Step 3: Find the number of candidates selected by both L and N.
To find the number of candidates selected by both L and N, we can rearrange the equation obtained in Step 2:
(Number of candidates selected by both L and N) = (28 * 100) / 50.

Now, we know that the total number of candidates selected by both L and N is 91.88% less than the total number of candidates selected by all three companies.
So, (Number of candidates selected by both L and N) = (8.12/100) * (Total number of candidates selected by all three companies).

Step 4: Find the total number of candidates selected by all three companies.
We can rearrange the equation obtained in Step 3 to find the total number of candidates selected by all three companies:
(Total number of candidates selected by all three companies) = (Number of candidates selected by both L and N) / (8.12/100).

Step 5: Find the number of candidates selected only by company L or M.
The number of candidates selected by both L and M is given as 60.
Since all three companies selected an equal number of candidates, the total number of candidates selected by L and M is twice the number of candidates selected by both L and M.
So, the total number of candidates selected by L and M = 2 * 60 = 120.

To find the number of candidates selected only by company L or M, we subtract the number of candidates placed in all three companies from the total number of candidates selected by L and M:
Number of candidates selected only by company L or M = (Total number of candidates selected by L and M) - (Number of candidates placed in all three companies).

Step 6: Calculate the final answer.
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Community Answer
Directions: Read the information carefully and answer the question.Th...
The Venn diagram for the given problem is as given in figure 1.
Firstly, there are 28 candidates placed in all the 3 companies.
So, 28 goes into the common region.
Then, 60 candidates were selected by both L and M.
So, 60 - 28 = 32 goes into the region common only to L and M.
Now, number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M.
Thus, number of candidates selected by both M and N = 2 × 60 - 68 = 120 - 68 = 52
Thus, 52 - 28 = 24 goes into the region common to both M and N.
Now, number of candidates selected by both L and N = 2 × 28 = 56
Thus, 56 - 28 = 28 goes into the region common to both L and N.
Now, let the total number of candidates selected = T
Number of candidates selected by both L and N = 56
So, 56 = T(1 - 0.9188) or T = 690
As equal number of candidates were selected by the 3 companies, the number of candidates in each company = 690/3 = 230
Thus, 230 - (32 + 28 + 28) = 230 - 88 = 142 goes into the region exclusive to L.
230 - (28 + 28 + 24) = 230 - 80 = 150 goes into the region exclusive to N.
230 - (32 + 28 + 24) = 230 - 84 = 146 goes into the region exclusive to M.
From the Venn diagram, it is clear that number of candidates selected by only L or M = Number of candidates selected by L or M and not by N = 142 + 32 + 146 = 320
Hence, answer option (c) is correct.
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Directions: Read the information carefully and answer the question.Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.Q. Find the total number of candidates who were selected only by company L or M.a)240b)260c)320d)None of theseCorrect answer is option 'C'. Can you explain this answer?
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Directions: Read the information carefully and answer the question.Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.Q. Find the total number of candidates who were selected only by company L or M.a)240b)260c)320d)None of theseCorrect answer is option 'C'. Can you explain this answer? for CLAT 2025 is part of CLAT preparation. The Question and answers have been prepared according to the CLAT exam syllabus. Information about Directions: Read the information carefully and answer the question.Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.Q. Find the total number of candidates who were selected only by company L or M.a)240b)260c)320d)None of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for CLAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Directions: Read the information carefully and answer the question.Three companies L, M and N participated for campus recruitment in college Z. All the three companies selected an equal number of candidates. There were 60 candidates who were selected by L and M both. The number of candidates selected by both M and N was 68 less than twice the number of candidates selected by both L and M. There were 28 candidates who got placed in all the 3 companies. This number was 50% less than the number of candidates selected by both L and N. The total number of candidates selected by both L and N was 91.88% less than total number of candidates selected by all the three company.Q. Find the total number of candidates who were selected only by company L or M.a)240b)260c)320d)None of theseCorrect answer is option 'C'. Can you explain this answer?.
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