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A force-time graph for a linear motion of a body is shown in the figure. The change in linear momentum between 0 and 7 s is
  • a)
    2 N-s
  • b)
    3 N-s
  • c)
    4 N-s
  • d)
    5 N-s
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A force-time graph for a linear motion of a body is shown in the figu...
Since, F = Δp/Δt
or Δp = FΔt
we can say that momentum between 0 to 7 s is equal to the vector area enclosed by the force-time graph from 0 to 7s.
So, Change in linear momentum = vector area of triangle OAB + vector area of square BCDE + vector area of triangle EFG + vector area of square GHIJ + vector area of triangle JKL
=
=
= 2 N-s
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A force-time graph for a linear motion of a body is shown in the figure. The change in linear momentum between 0 and 7 s isa)2 N-sb)3 N-sc)4 N-sd)5 N-sCorrect answer is option 'A'. Can you explain this answer?
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