NEET Exam > NEET Questions > Particle of mass 2kg travelling along X axis ...
Start Learning for Free
Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).?
Most Upvoted Answer
Particle of mass 2kg travelling along X axis at 10 m/s changes its vel...
**Given Data:**
- Mass of the particle, m = 2 kg
- Initial velocity along the x-axis, u = 10 m/s
- Final velocity along the y-axis, v = 10 m/s
- Time taken, t = 5 s
**Determination of Change in Linear Momentum:**
The change in linear momentum of an object is given by the formula:
Δp = m * (v - u)
where Δp is the change in linear momentum, m is the mass of the object, v is the final velocity, and u is the initial velocity.
**Determination of Change in Linear Momentum in the i-component:**
As the particle changes its velocity from the x-axis to the y-axis, the change in linear momentum in the i-component can be determined by considering the change in velocity along the x-axis.
Δp_i = m * (v_i - u_i)
where Δp_i is the change in linear momentum in the i-component, m is the mass of the particle, v_i is the final velocity along the x-axis, and u_i is the initial velocity along the x-axis.
Since the particle's velocity changes from 10 m/s along the x-axis to 0 m/s along the x-axis, the change in linear momentum in the i-component can be calculated as:
Δp_i = 2 kg * (0 m/s - 10 m/s)
Δp_i = -20 kg·m/s
Therefore, the magnitude of the change in linear momentum in the i-component is 20 kg·m/s, and the direction is negative along the x-axis.
**Determination of Change in Linear Momentum in the j-component:**
As the particle changes its velocity from the x-axis to the y-axis, the change in linear momentum in the j-component can be determined by considering the change in velocity along the y-axis.
Δp_j = m * (v_j - u_j)
where Δp_j is the change in linear momentum in the j-component, m is the mass of the particle, v_j is the final velocity along the y-axis, and u_j is the initial velocity along the y-axis.
Since the particle's velocity changes from 0 m/s along the y-axis to 10 m/s along the y-axis, the change in linear momentum in the j-component can be calculated as:
Δp_j = 2 kg * (10 m/s - 0 m/s)
Δp_j = 20 kg·m/s
Therefore, the magnitude of the change in linear momentum in the j-component is 20 kg·m/s, and the direction is positive along the y-axis.
**Summary:**
The magnitude and direction of the change in linear momentum in component (i,j) are as follows:
- Change in Linear Momentum in the i-component: 20 kg·m/s, negative along the x-axis
- Change in Linear Momentum in the j-component: 20 kg·m/s, positive along the y-axis
- Mass of the particle, m = 2 kg
- Initial velocity along the x-axis, u = 10 m/s
- Final velocity along the y-axis, v = 10 m/s
- Time taken, t = 5 s
**Determination of Change in Linear Momentum:**
The change in linear momentum of an object is given by the formula:
Δp = m * (v - u)
where Δp is the change in linear momentum, m is the mass of the object, v is the final velocity, and u is the initial velocity.
**Determination of Change in Linear Momentum in the i-component:**
As the particle changes its velocity from the x-axis to the y-axis, the change in linear momentum in the i-component can be determined by considering the change in velocity along the x-axis.
Δp_i = m * (v_i - u_i)
where Δp_i is the change in linear momentum in the i-component, m is the mass of the particle, v_i is the final velocity along the x-axis, and u_i is the initial velocity along the x-axis.
Since the particle's velocity changes from 10 m/s along the x-axis to 0 m/s along the x-axis, the change in linear momentum in the i-component can be calculated as:
Δp_i = 2 kg * (0 m/s - 10 m/s)
Δp_i = -20 kg·m/s
Therefore, the magnitude of the change in linear momentum in the i-component is 20 kg·m/s, and the direction is negative along the x-axis.
**Determination of Change in Linear Momentum in the j-component:**
As the particle changes its velocity from the x-axis to the y-axis, the change in linear momentum in the j-component can be determined by considering the change in velocity along the y-axis.
Δp_j = m * (v_j - u_j)
where Δp_j is the change in linear momentum in the j-component, m is the mass of the particle, v_j is the final velocity along the y-axis, and u_j is the initial velocity along the y-axis.
Since the particle's velocity changes from 0 m/s along the y-axis to 10 m/s along the y-axis, the change in linear momentum in the j-component can be calculated as:
Δp_j = 2 kg * (10 m/s - 0 m/s)
Δp_j = 20 kg·m/s
Therefore, the magnitude of the change in linear momentum in the j-component is 20 kg·m/s, and the direction is positive along the y-axis.
**Summary:**
The magnitude and direction of the change in linear momentum in component (i,j) are as follows:
- Change in Linear Momentum in the i-component: 20 kg·m/s, negative along the x-axis
- Change in Linear Momentum in the j-component: 20 kg·m/s, positive along the y-axis
Community Answer
Particle of mass 2kg travelling along X axis at 10 m/s changes its vel...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).?
Question Description
Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).?.
Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).?.
Solutions for Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? defined & explained in the simplest way possible. Besides giving the explanation of
Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).?, a detailed solution for Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? has been provided alongside types of Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? theory, EduRev gives you an
ample number of questions to practice Particle of mass 2kg travelling along X axis at 10 m/s changes its velocity to 10 m/s along y axis in 5 seconds under the influence of a force. determine the magnitude and direction of change in linear momentum in component (I,j).? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup