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A particle moves in the x y plane under the action of a force f such that the value of its linear momentum p at any time t is px=2cost, py=2 sin t, the angle kitta between f and p at a given time t will be?
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A particle moves in the x y plane under the action of a force f such t...
Force F is nothing but rate of change of momentum.
Hence,  F = dP/dt
Given, Px = 2cost  &  Py = 2sint
=> Fx = -2sint   &   Fy = 2cost
Now to find the angle between the force vector and the momentum vector, let us first find the dot product of these two vectors.
F.P = FxPx + FyPy
       = 2cost*-2sint + 2sint*2cost
       = -4cost*sint + 4cost*sint
       =  0
Also, F.P = |F||P|cosθ

=>  cosθ = 0
=>  θ = 90 degrees.
Hence, the angle between force and momentum vectors is 90 degrees

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A particle moves in the x y plane under the action of a force f such that the value of its linear momentum p at any time t is px=2cost, py=2 sin t, the angle kitta between f and p at a given time t will be?
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A particle moves in the x y plane under the action of a force f such that the value of its linear momentum p at any time t is px=2cost, py=2 sin t, the angle kitta between f and p at a given time t will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A particle moves in the x y plane under the action of a force f such that the value of its linear momentum p at any time t is px=2cost, py=2 sin t, the angle kitta between f and p at a given time t will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle moves in the x y plane under the action of a force f such that the value of its linear momentum p at any time t is px=2cost, py=2 sin t, the angle kitta between f and p at a given time t will be?.
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