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The zero magnetic moment of octahedral K2NiF6 is due to
- a)Low spin d6Ni(IV) complex
- b)Low spin d8Ni(IV) complex
- c)High spin d8Ni(IV) complex
- d)High spin d6Ni(IV) complex
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The zero magnetic moment of octahedral K2NiF6 is due toa)Low spin d6Ni...
A low spin complex is formed when the ligands are of strong field strength whereas high spin is characterised by weak field strength.
In K2NiF6 , Ni is in +4 oxidation state with d6 electronic configuration.Here fluoride acts as a strong field ligand resulting in low spin complex.
In a strong field, all of the electrons in d6 are paired up, leaving zero unpaired electrons, corresponding to a zero magnetic moment.
Note: When metal is in +4 oxidation state all ligands act as strong field ligands.
In K2NiF6 , Ni is in +4 oxidation state with d6 electronic configuration.Here fluoride acts as a strong field ligand resulting in low spin complex.
In a strong field, all of the electrons in d6 are paired up, leaving zero unpaired electrons, corresponding to a zero magnetic moment.
Note: When metal is in +4 oxidation state all ligands act as strong field ligands.
Most Upvoted Answer
The zero magnetic moment of octahedral K2NiF6 is due toa)Low spin d6Ni...
A low spin complex is formed when the ligands are of strong field strength whereas high spin is characterised by weak field strength.
In K2NiF6 , Ni is in +4 oxidation state with d6 electronic configuration.Here fluoride acts as a strong field ligand resulting in low spin complex.
In a strong field, all of the electrons in d6 are paired up, leaving zero unpaired electrons, corresponding to a zero magnetic moment.
Note: When metal is in +4 oxidation state all ligands act as strong field ligands.
In K2NiF6 , Ni is in +4 oxidation state with d6 electronic configuration.Here fluoride acts as a strong field ligand resulting in low spin complex.
In a strong field, all of the electrons in d6 are paired up, leaving zero unpaired electrons, corresponding to a zero magnetic moment.
Note: When metal is in +4 oxidation state all ligands act as strong field ligands.
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The zero magnetic moment of octahedral K2NiF6 is due toa)Low spin d6Ni...
Understanding K2NiF6 and its Magnetic Moment
K2NiF6 is a coordination compound where nickel is in the +4 oxidation state (Ni(IV)). To understand why it has a zero magnetic moment, we need to analyze the electronic configuration and the spin state of the nickel ion.
Electronic Configuration of Ni(IV)
- Nickel (Ni) has the atomic number 28, and in the +4 oxidation state, its electron configuration becomes:
- d6 (removing 4 electrons from the neutral configuration).
Octahedral Field Splitting
- In an octahedral field, the d-orbitals split into two sets:
- Lower energy (t2g) and higher energy (eg) orbitals.
- For d6 configurations, the electrons can either fill the lower energy orbitals first (low spin) or fill them according to Hund's rule (high spin).
Low Spin vs. High Spin
- Low Spin d6 (Ni(IV)):
- In strong field ligands like F-, the electrons pair up in the t2g orbitals first before occupying the eg orbitals.
- This results in no unpaired electrons, leading to a zero magnetic moment.
- High Spin d6 (Ni(IV)):
- If it were high spin, the electrons would remain unpaired, resulting in a measurable magnetic moment.
Conclusion
- Since K2NiF6 contains low spin d6 Ni(IV) ions, all electrons are paired, resulting in a zero magnetic moment.
- Therefore, the correct answer is option 'A': Low spin d6 Ni(IV) complex.
K2NiF6 is a coordination compound where nickel is in the +4 oxidation state (Ni(IV)). To understand why it has a zero magnetic moment, we need to analyze the electronic configuration and the spin state of the nickel ion.
Electronic Configuration of Ni(IV)
- Nickel (Ni) has the atomic number 28, and in the +4 oxidation state, its electron configuration becomes:
- d6 (removing 4 electrons from the neutral configuration).
Octahedral Field Splitting
- In an octahedral field, the d-orbitals split into two sets:
- Lower energy (t2g) and higher energy (eg) orbitals.
- For d6 configurations, the electrons can either fill the lower energy orbitals first (low spin) or fill them according to Hund's rule (high spin).
Low Spin vs. High Spin
- Low Spin d6 (Ni(IV)):
- In strong field ligands like F-, the electrons pair up in the t2g orbitals first before occupying the eg orbitals.
- This results in no unpaired electrons, leading to a zero magnetic moment.
- High Spin d6 (Ni(IV)):
- If it were high spin, the electrons would remain unpaired, resulting in a measurable magnetic moment.
Conclusion
- Since K2NiF6 contains low spin d6 Ni(IV) ions, all electrons are paired, resulting in a zero magnetic moment.
- Therefore, the correct answer is option 'A': Low spin d6 Ni(IV) complex.
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