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Find the number of digits in ‘N’ where N = 210 × 72 × 35. It is given that- log102 = 0.301, log103 = 0.477 and log107 = 0.845.
Correct answer is '8'. Can you explain this answer?
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Find the number of digits in ‘N’ where N = 210 × 72 × 35. It is given...
The number of digits in any number ‘N’ is equal to [x] + 1, where [.] is a floor function and x=log10N
Now, N = 210 × 72 × 35
log10N = log10(210 × 72 × 35)
log10N = log10(210) + log10(72) + log10(35)
log10N = 10log102 + 2log107 + 5log103
log10N = 10 × 0.301 + 2 × 0.845 + 5 × 0.477
log10N = 7.085
So, required digits = 7 + 1 = 8
Hence, the correct answer is 8.
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Find the number of digits in ‘N’ where N = 210 × 72 × 35. It is given...
Number of digits in N = 210 × 72 × 35

To find the number of digits in N, we need to determine the value of N first by multiplying the given numbers.

Step 1: Calculate the value of N
N = 210 × 72 × 35
N = 529200 × 35
N = 18,517,200

Step 2: Find the number of digits in N
To determine the number of digits in N, we can take the logarithm of N to the base 10 and add 1 to the result. This will give us the total number of digits in N.

Using the logarithmic properties, we can simplify the calculation as follows:

log(N) = log(18,517,200)
log(N) = log(529200) + log(35)
log(N) = log(2^4 × 5^2 × 5292) + log(5 × 7)
log(N) = 4log(2) + 2log(5) + log(5292) + log(5) + log(7)
log(N) = 4(0.301) + 2(0.477) + log(5292) + log(5) + log(7)
log(N) = 1.204 + 0.954 + log(5292) + log(5) + log(7)
log(N) = 2.158 + log(5292) + log(5) + log(7)

Now, we need to determine the values of log(5292), log(5), and log(7) using the given information.

Given:
log(5) = 0.301
log(7) = 0.845

To find log(5292), we can break it down further:
5292 = 2^2 × 3 × 7^2 × 7

Using logarithmic properties, we can simplify the calculation as follows:
log(5292) = log(2^2 × 3 × 7^2 × 7)
log(5292) = 2log(2) + log(3) + 2log(7) + log(7)
log(5292) = 2(0.301) + log(3) + 2(0.845) + log(7)
log(5292) = 0.602 + log(3) + 1.69 + log(7)
log(5292) = 2.292 + log(3) + log(7)

Now, substituting the values back into the previous equation:
log(N) = 2.158 + 2.292 + log(3) + log(7) + 0.301 + 0.845
log(N) = 5.596 + log(3) + log(7)

Step 3: Calculate the value of N
To determine the value of N, we need to convert the logarithmic expression back into its exponential form.

N = 10^(log(N))
N = 10^(5.596 + log(3) + log(7))

Now, we can calculate N using the given values of log(3) and log(7
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Find the number of digits in ‘N’ where N = 210 × 72 × 35. It is given that- log102 = 0.301, log103 = 0.477 and log107 = 0.845.Correct answer is '8'. Can you explain this answer?
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Find the number of digits in ‘N’ where N = 210 × 72 × 35. It is given that- log102 = 0.301, log103 = 0.477 and log107 = 0.845.Correct answer is '8'. Can you explain this answer? for CAT 2025 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about Find the number of digits in ‘N’ where N = 210 × 72 × 35. It is given that- log102 = 0.301, log103 = 0.477 and log107 = 0.845.Correct answer is '8'. Can you explain this answer? covers all topics & solutions for CAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the number of digits in ‘N’ where N = 210 × 72 × 35. It is given that- log102 = 0.301, log103 = 0.477 and log107 = 0.845.Correct answer is '8'. Can you explain this answer?.
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