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Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty are
  • a)
    Full: (REAR+1) mod n == FRONT, empty: REAR == FRONT
  • b)
    Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REAR
  • c)
    Full: REAR == FRONT, empty: (REAR+1) mod n == FRONT
  • d)
    Full: (FRONT+1) mod n == REAR, empty: REAR == FRONT
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Suppose a circular queue of capacity (n – 1) elements is impleme...
A circular queue is a data structure that follows the FIFO (First In First Out) principle and has a fixed capacity. It is implemented using a circular array, which means that the last element is connected to the first element, forming a circle.

To implement a circular queue of capacity (n), we need to define the following:

1. A circular array of size n to hold the elements of the queue.
2. Two pointers - front and rear, to keep track of the elements in the queue.
3. A variable - count, to keep track of the number of elements in the queue.

Initially, both front and rear pointers are set to -1, indicating an empty queue. Whenever an element is added to the queue, the rear pointer is incremented by 1, and the element is added to the array at the rear index. If the rear pointer exceeds the array size, it is set to 0, indicating that the queue has wrapped around.

Similarly, whenever an element is removed from the queue, the front pointer is incremented by 1, and the element at the front index is removed from the array. If the front pointer exceeds the array size, it is set to 0, indicating that the queue has wrapped around.

To check if the queue is full, we need to compare the count variable with the capacity (n). If count is equal to n, the queue is full. To check if the queue is empty, we need to check if both front and rear pointers are -1. If they are, the queue is empty.

Here is the implementation of a circular queue of capacity (n) in Python:

```
class CircularQueue:
def __init__(self, capacity):
self.capacity = capacity
self.queue = [None] * capacity
self.front = -1
self.rear = -1
self.count = 0

def enqueue(self, item):
if self.is_full():
print("Queue is full")
return
if self.front == -1:
self.front = 0
self.rear = (self.rear + 1) % self.capacity
self.queue[self.rear] = item
self.count += 1

def dequeue(self):
if self.is_empty():
print("Queue is empty")
return
item = self.queue[self.front]
self.queue[self.front] = None
if self.front == self.rear:
self.front = -1
self.rear = -1
else:
self.front = (self.front + 1) % self.capacity
self.count -= 1
return item

def is_full(self):
return self.count == self.capacity

def is_empty(self):
return self.front == -1

def size(self):
return self.count
```

In this implementation, the enqueue() function adds an element to the rear of the queue, and the dequeue() function removes an element from the front of the queue. The is_full() function checks if the queue is full, and the is_empty() function checks if the queue is empty. The size() function returns the number of elements in the queue.

Note that the modulo operator (%) is used to wrap around the rear and front pointers when they exceed the array size. This ensures that the circular queue works correctly even if the front pointer is ahead of the rear pointer in
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Community Answer
Suppose a circular queue of capacity (n – 1) elements is impleme...
Suppose we start filling the queue.
Let the maxQueueSize ( Capacity of the Queue) is 4. So the size of the array which is used to implement this circular queue is 5, which is n.
In the beginning when the queue is empty, FRONT and REAR point to 0 index in the array.
REAR represents insertion at the REAR index.
FRONT represents deletion from the FRONT index.
enqueue("a"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 1)
enqueue("b"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 2)
enqueue("c"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 3)
enqueue("d"); REAR = (REAR+1)%5; ( FRONT = 0, REAR = 4)
Now the queue size is 4 which is equal to the maxQueueSize. 
Hence overflow condition is reached.
Now, we can check for the conditions.
When Queue Full :
(REAR+1)%n = (4+1)%5 = 0
FRONT is also 0.
Hence ( REAR + 1 ) %n is equal to FRONT.
When Queue Empty :
REAR was equal to FRONT when empty ( because in the starting 
before filling the queue FRONT = REAR = 0 )
Hence Option A is correct.
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Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer?
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Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Suppose a circular queue of capacity (n – 1) elements is implemented with an array of n elements. Assume that the insertion and deletion operation are carried out using REAR and FRONT as array index variables, respectively. Initially, REAR = FRONT = 0. The conditions to detect queue full and queue empty area)Full: (REAR+1) mod n == FRONT, empty: REAR == FRONTb)Full: (REAR+1) mod n == FRONT, empty: (FRONT+1) mod n == REARc)Full: REAR == FRONT, empty: (REAR+1) mod n == FRONTd)Full: (FRONT+1) mod n == REAR, empty: REAR == FRONTCorrect answer is option 'A'. Can you explain this answer?.
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