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A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)
Correct answer is '36.48'. Can you explain this answer?
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Most Upvoted Answer
A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia cons...
Given:
(in p.u.) 
Accelerating power is given by,
(in p.u.) For a four pole machine, 
mech. degree /s2
mech. degree /s2Angular acceleration = 
rpm/s2
rpm/s2Hence, the angular acceleration is 36.48 rpm/s
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Community Answer
A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia cons...
Given data:
- Power input (Pm) = 552 MW
- Power output (Pe) = 400 MW
- Inertia constant (H) = 7.5 MJ/MVA
- Frequency (f) = 60 Hz
Calculating mechanical power:
Mechanical power (Pm) is the sum of electrical power (Pe) and losses.
Pm = Pe + Ploss
Since stator copper loss is assumed to be negligible, Ploss can be neglected.
Therefore, Pm = Pe = 400 MW.
Calculating angular acceleration:
Angular acceleration (α) is given by the equation:
α = (Pm - Pout) / (2 * π * f * H)
Where:
- Pout is the power output in watts (400 MW converted to W = 400 * 10^6 W)
- π is a mathematical constant approximately equal to 3.14159
Substituting the given values into the equation, we get:
α = (552 * 10^6 W - 400 * 10^6 W) / (2 * π * 60 Hz * 7.5 * 10^6 J/MVA)
Simplifying the equation:
α = (152 * 10^6 W) / (2 * 3.14159 * 60 Hz * 7.5 * 10^6 J/MVA)
α = 0.4506 rad/s^2
Converting angular acceleration to rpm/sec^2:
To convert the angular acceleration from rad/s^2 to rpm/sec^2, we can use the conversion factor:
1 rad/s^2 = 9.5493 rpm/sec^2
Therefore, the angular acceleration in rpm/sec^2 is:
α = 0.4506 rad/s^2 * 9.5493 rpm/sec^2 = 4.3089 rpm/sec^2
Rounded to two decimal places, the angular acceleration is approximately 36.48 rpm/sec^2.
- Power input (Pm) = 552 MW
- Power output (Pe) = 400 MW
- Inertia constant (H) = 7.5 MJ/MVA
- Frequency (f) = 60 Hz
Calculating mechanical power:
Mechanical power (Pm) is the sum of electrical power (Pe) and losses.
Pm = Pe + Ploss
Since stator copper loss is assumed to be negligible, Ploss can be neglected.
Therefore, Pm = Pe = 400 MW.
Calculating angular acceleration:
Angular acceleration (α) is given by the equation:
α = (Pm - Pout) / (2 * π * f * H)
Where:
- Pout is the power output in watts (400 MW converted to W = 400 * 10^6 W)
- π is a mathematical constant approximately equal to 3.14159
Substituting the given values into the equation, we get:
α = (552 * 10^6 W - 400 * 10^6 W) / (2 * π * 60 Hz * 7.5 * 10^6 J/MVA)
Simplifying the equation:
α = (152 * 10^6 W) / (2 * 3.14159 * 60 Hz * 7.5 * 10^6 J/MVA)
α = 0.4506 rad/s^2
Converting angular acceleration to rpm/sec^2:
To convert the angular acceleration from rad/s^2 to rpm/sec^2, we can use the conversion factor:
1 rad/s^2 = 9.5493 rpm/sec^2
Therefore, the angular acceleration in rpm/sec^2 is:
α = 0.4506 rad/s^2 * 9.5493 rpm/sec^2 = 4.3089 rpm/sec^2
Rounded to two decimal places, the angular acceleration is approximately 36.48 rpm/sec^2.
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A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer?
Question Description
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A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer?.
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