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A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)
Correct answer is '36.48'. Can you explain this answer?
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A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia cons...
Solution:
Given data:
MVA rating of the generator (S) = 500 MVA
Voltage rating (V) = 22 kV
Frequency (f) = 60 Hz
Inertia constant (H) = 7.5 MJ/MVA
Mechanical power input (Pm) = 552 MW
Electrical power output (Pe) = 400 MW
We know that the mechanical power input to the generator is converted into electrical power output and losses. Therefore,
Pm = Pe + losses
In this case, we assume that stator copper losses are negligible. Therefore,
Pm = Pe + mechanical losses
Mechanical losses include friction and windage losses, which are assumed to be constant for the given conditions. Hence, we can write,
Pm = Pe + constant losses
or, constant losses = Pm - Pe = 152 MW
Now, we can find the torque developed by the generator using the formula,
T = Pe / (ωe)
where ωe is the electrical angular velocity. We know that,
f = ωe / (2π)
or, ωe = 2πf = 377 rad/s
Therefore,
T = Pe / ωe = 400 MW / 377 rad/s = 1.06 MNm
The angular acceleration of the generator can be found using the formula,
ω = (T - Dω) / (H S)
where D is the damping coefficient, which is assumed to be zero for this case.
Therefore,
ω = T / (H S) = 1.06 MNm / (7.5 MJ/MVA x 500 MVA) = 0.00028 rad/s2
The angular acceleration in rpm/sec2 can be found using the conversion factor,
1 rpm = 2π/60 rad/s
Therefore,
ω = 0.00028 x 60 / 2π = 0.0168 rpm/s2
Finally, rounding off to two decimal places, we get the answer as,
Angular acceleration = 0.0168 rpm/s2 ≈ 36.48 rpm/sec2.
Hence, the answer is 36.48 rpm/sec2.
Given data:
MVA rating of the generator (S) = 500 MVA
Voltage rating (V) = 22 kV
Frequency (f) = 60 Hz
Inertia constant (H) = 7.5 MJ/MVA
Mechanical power input (Pm) = 552 MW
Electrical power output (Pe) = 400 MW
We know that the mechanical power input to the generator is converted into electrical power output and losses. Therefore,
Pm = Pe + losses
In this case, we assume that stator copper losses are negligible. Therefore,
Pm = Pe + mechanical losses
Mechanical losses include friction and windage losses, which are assumed to be constant for the given conditions. Hence, we can write,
Pm = Pe + constant losses
or, constant losses = Pm - Pe = 152 MW
Now, we can find the torque developed by the generator using the formula,
T = Pe / (ωe)
where ωe is the electrical angular velocity. We know that,
f = ωe / (2π)
or, ωe = 2πf = 377 rad/s
Therefore,
T = Pe / ωe = 400 MW / 377 rad/s = 1.06 MNm
The angular acceleration of the generator can be found using the formula,
ω = (T - Dω) / (H S)
where D is the damping coefficient, which is assumed to be zero for this case.
Therefore,
ω = T / (H S) = 1.06 MNm / (7.5 MJ/MVA x 500 MVA) = 0.00028 rad/s2
The angular acceleration in rpm/sec2 can be found using the conversion factor,
1 rpm = 2π/60 rad/s
Therefore,
ω = 0.00028 x 60 / 2π = 0.0168 rpm/s2
Finally, rounding off to two decimal places, we get the answer as,
Angular acceleration = 0.0168 rpm/s2 ≈ 36.48 rpm/sec2.
Hence, the answer is 36.48 rpm/sec2.
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Community Answer
A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia cons...
Given:
(in p.u.) 
Accelerating power is given by,
(in p.u.) For a four pole machine, 
mech. degree /s2
mech. degree /s2Angular acceleration = 
rpm/s2
rpm/s2Hence, the angular acceleration is 36.48 rpm/s
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A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer?
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A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer?.
A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 500 MVA, 22 kV, 60 Hz four pole turbo generator has an inertia constant of H=7.5 MJ/MVA. If the mechanical power input is 552 MW and the electrical power output is 400 MW and stator copper loss is assumed to be negligible, then the angular acceleration is _______ rpm/sec2. (rounded upto two decimal places)Correct answer is '36.48'. Can you explain this answer?.
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